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babymother [125]
3 years ago
11

Pleaseeeeeeee helppppppp

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:

138°

Step-by-step explanation:

69X2=138

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$75, $97, $360, $84, $119, $100 Find the median<br> a. 45<br> b. 98.5<br> C. 97<br> d. 100
mafiozo [28]

Answer:

C.97

Step-by-step explanation:

5 0
3 years ago
Two cylinders are similar. The radius of cylinder A is 5.6 inches. The radius of cylinder B is 1.4 inches. If the height of cyli
natita [175]
The answer is 16 inches.

Let r be a radius and h be a height of a cylinder
Since the cylinders are similar, then the ratio between their radiuses is equal to the ratio of their heights:
r1 : r2 = h1 : h2

Cylinder A:
r1 = 5.6 in
h1 = ?

Cylinder B:
r2 = 1.4 in
h2 = 4 in

5.6 : 1.4 = h1 : 4
h1 = 4 * 5.6 : 1.4
h1 = 16 inches
7 0
4 years ago
Read 2 more answers
4(2 + 4x) please help
ladessa [460]
The answer is 8+16x
6 0
3 years ago
Consider the differential equation,
kondor19780726 [428]

Answer:

The two solutions are given as y_1(t)=\dfrac{1}{9}e^{-8t}+\dfrac{8}{9}e^{t} and y_2(t)=\dfrac{-1}{9}e^{-8t}+\dfrac{1}{9}e^{t}

Step-by-step explanation:

As the given equation is

y''+7y'-8y=0\\

So the corresponding equation is given as

m^2+7m-8=0

Solving this equation yields the value of m as

(m+8)(m-1)=0\\m=-8, m=1

Now the equation is given as

y(t)=C_1e^{m_1t}+C_2e^{m_2t}

Here m1=-8, m2=1 so

y(t)=C_1e^{-8t}+C_2e^{t}

The derivative is given as

y'(t)=-8C_1e^{-8t}+C_2e^{t}

Now for the first case y(t=0)=1, y'(t=0)=0

y(t=0)=C_1e^{-8*0}+C_2e^{0}\\1=C_1+C_2\\\\y'(t=0)=-8C_1e^{-8*0}+C_2e^{0}\\0=-8C_1+C_2

So the two equation of co-efficient are given as

C_1+C_2=1\\-8C_1+C_2=0

Solving the equation yield

C_1=1/9 \\C_2=8/9

So the function is given as

y_1(t)=\dfrac{1}{9}e^{-8t}+\dfrac{8}{9}e^{t}

Now for the second case y(t=0)=0, y'(t=0)=1

y(t=0)=C_1e^{-8*0}+C_2e^{0}\\0=C_1+C_2\\\\y'(t=0)=-8C_1e^{-8*0}+C_2e^{0}\\1=-8C_1+C_2

So the two equation of co-efficient are given as

C_1+C_2=0\\-8C_1+C_2=1

Solving the equation yield

C_1=-1/9 \\C_2=1/9

So the function is given as

y_2(t)=\dfrac{-1}{9}e^{-8t}+\dfrac{1}{9}e^{t}

So the two solutions are given as y_1(t)=\dfrac{1}{9}e^{-8t}+\dfrac{8}{9}e^{t} and y_2(t)=\dfrac{-1}{9}e^{-8t}+\dfrac{1}{9}e^{t}

7 0
3 years ago
A family pays $45 each month for cable television. The cost increases by 7%.
tatiyna
$76.5 is how much they pay now and it increased by 31.5
6 0
3 years ago
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