Given:
Initial price of the stock=$43.85
Change for the first two days=+$2.70
Change for next two days=-$1.10
Last day=-$4.45
The objective is to find the price at the last day.
Let's take the price at final day as <em>x</em>.
Hence, the price of the stock at the last day is $42.6
Answer:
12/13
Step-by-step explanation:
Given that MN = 5, NO = 12, and MO = 13, find cos O.
Since the reference angle is P, hence;
MN is the opposite = 5
MO is the hypotenuse = 13 (longest side)
NO is the adjacent = 12
Cos O = adj/hyp
Substitute the given values
Cos O = 12/13
Hence the value of Cos O is 12/13
The inequality would be 34 > 2 x 3, if I'm correct. I'm not to sure on the graph part though , sorry.
Answer:
-0.6309
Step-by-step explanation:
Using the change of base formula,
Log 1/2 to base 3 = Log1/2 ÷ Log 3 = Log 0.5 ÷ Log 3
Log 0.5 = -0.3010
Log3 = 0.4771
Log 0.5 ÷ Log 3 = -0.3010 ÷ 0.4771 = -0.6309
34.50/6 = 5.75
44/8 = 5.5
52.5/10 = 5.25
As the number of tickets increase, the cost per ticket decreases.
So it does not make sense to use a constant rate.
