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Nimfa-mama [501]
3 years ago
12

Any answer? Stuck on this one

Mathematics
1 answer:
OLga [1]3 years ago
4 0
The answer is A dixjdbdi
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Solve the inequality graph and check the solution.<br> 5&gt;z-3
AnnZ [28]

Answer:

z < 8

Step-by-step explanation:

Add 3 to both sides

8 > z OR z < 8

7 0
3 years ago
1) how many significant digits are there in the sum of 45.10 and 102.203?
Sergio039 [100]
Oi  :)

1) There are 3 significant digits
45.10+102.203= 147.303

2)
15 Mi/h  =  22 ft/s

3)
C= 72*m* \frac{3}{4} \\  \\ C= 72*81* \frac{3}{4} \\  \\ C= \frac{17496}{4}  \\  \\ C=4374

4)
There are 4 significant digitis. Leter C 
7 0
3 years ago
What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?<br><br> –10<br> –5<br> –3<br> –1
givi [52]

Answer: -1

Step-by-step explanation:

Given by your question

2(3x-1)≥4x-6

Distributive property to take off the parentheses

2×3x-2×1≥4x-6

6x-2≥4x-6

Subtract 4x on both sides (Subtractive property of equality)

6x-2-4x≥4x-6-4x

2x-2≥-6

Add 2 on both sides (Addition property of equality)

2x-2+2≥-6+2

2x≥-4

Divide 2 on both sides (Division property of equality)

2/2 x≥-4/2

x≥-2

----------------------------------------------------------------------------

Looking at the options you've provided.

-10 INCORRECT, it is not greater or equal to -2

-5 INCORRECT, it is not greater or equal to -2

-3 INCORRECT, it is not greater or equal to -2

-1 CORRECT, it is greater than -2

Hope this helps!! :)

Please let me know if you have any question

8 0
3 years ago
Read 2 more answers
Answer the question in the picture.
Rama09 [41]

Answer:

4

Step-by-step explanation:

have a nice day

4 0
3 years ago
Read 2 more answers
If GF is a midsegment of CDE, find CD.<br><br> A. 3.4<br><br>B. 6.8 <br><br>C. 13.6 <br><br>D. 14
bogdanovich [222]

Answer:

C


Step-by-step explanation:

Triangle CGF and triangle CED are similar. Hence, the ratio of their corresponding sides are equal. Thus we can write:

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}

<em>We can now cross multiply and solve for CD:</em>

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}\\(5x+4)(3x+0.8)=(2x+3)(CD)\\15x^2+4x+12x+3.2=(2x+3)(CD)\\15x^2+16x+3.2=(2x+3)(CD)\\CD=\frac{15x^2+16x+3.2}{2x+3}

Since GF is a midsegment of CDE, CD is double of CF. So we can write:

CD=2CF\\\frac{15x^2+16x+3.2}{2x+3}=2(3x+0.8)\\\frac{15x^2+16x+3.2}{2x+3}=6x+1.6\\15x^2+16x+3.2=(6x+1.6)(2x+3)\\15x^2+16x+3.2=12x^2+18x+3.2x+4.8\\15x^2+16x+3.2=12x^2+21.2x+4.8\\3x^2-5.2x-1.6=0

<em>By using quadratic formula \frac{-b+-\sqrt{b^2-4ac} }{2a} and with a=3, b= -5.2, and c= -1.6, we find the value of x to be:</em>

\frac{5.2+-\sqrt{(-5.2)^2-4(3)(-1.6)} }{2(3)}=2


<em>Since the expression for CD is \frac{15x^2+16x+3.2}{2x+3} , we plug in x=2 into this expression to find value of CD:</em>

\frac{15(2)^2+16(2)+3.2}{2(2)+3}=13.6

The correct answer is C

6 0
2 years ago
Read 2 more answers
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