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1 year ago

8

1.

1 answer:

Tems11 [23]1 year ago

5 0

Answer:

b

Step-by-step explanation:

b

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Answer correctly plz

Ne4ueva [31]

Answer:

1/3

Step-by-step explanation:

Use the Up/to left or right rule to help you

Find a start point (or the one the gave you (3,2)) and then follow the line to the next point that crosses exactly over where to points cross (where poth x and y would be whole numbers) count how many times the point moved up, then how many time it moved left. Put the first over the second in fraction form and there is your slope.

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1 year ago

Read 2 more answers

The surface area 5cm x 14cm x 6cm

Rom4ik [11]

The surface is the sun of all the sides. With the information provide I can only work out the volume, which is 420cm^3

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2 years ago

Ants have 6 legs. Katie and Lukas write equations showing the proportional relationship between the number of ants, a, and the n

krek1111 [17]

Answer:

A

Step-by-step explanation:

I agree with Katie because number is legs is directly proportional to the number of ants.

1 ant has 6 legs.

So, 2 ants have 6 *2 = 12

3 ants have 6*3 = 18

6 0

1 year ago

Evaluate [(40 + 5) − 32] ÷ 9 ⋅ 2.

CaHeK987 [17]

(45 - 32) / 9 * 2
13 / 18

the. answer is 13 / 18

3 0

2 years ago

Read 2 more answers

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

2 years ago