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Contact [7]
2 years ago
5

What is an equation of the line that passes through the points (0, 3) and (5, -3)?

Mathematics
1 answer:
ANEK [815]2 years ago
7 0
I believe the answer is Y=-5/6x +3
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I need to understand how to solve this equation step by step
Ipatiy [6.2K]
So in order to get rid of the cubed roots, you must cube each side of the equation. what you do to one side you do to the other at all times. so when you cube a cubed root, you get whats in side. so after the first step, you should get x+5=8(2x+6) now distribute the 8 on the right side of the equation and get x+5=16x+48solve for x and get x=-43/15
5 0
3 years ago
Tony’s Electronics is marking down the price of a TV 23% from the original price of $175. Which expression can be used to find t
Arlecino [84]

Answer:

The sale price is \$134.75

The expression is \$175(0.77)

Step-by-step explanation:

we know that

The sale price is equal to subtract the discount price from the original price

The discount price is equal to multiply the original price by the percent discount in decimal form

Let

x ----> the sale price

y ---> discount price

23\%=23/100=0.23 ----> percent discount in decimal form

y=\$175(0.23)=\$40.25

x=\$175-y

substitute

x=\$175-\$40.25=\$134.75

therefore

the expression is

175-0.23(175)\\175(1-0.23)\\175(0.77)

3 0
3 years ago
Read 2 more answers
Look at the rectangle and the square:
OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = \sqrt{180} ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = \sqrt{72} ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

5 0
2 years ago
Read 2 more answers
7/13 of the population of a town is female.of the males 2/3 are married,What fraction population consists of unmarried men?​
Mariana [72]

Answer:

Step-by-step explanation:

\frac{7}{13}-Female

\frac{2}{3}- Men Married.

\frac{7}{13}  divided by \frac{2}{3} = \frac{7}{13} x\frac{3}{2} = \frac{21}{6} = 3\frac{2}{6} = 3\frac{1}{3}

Hope this helps :)

3 0
3 years ago
What is 4and1/2 subtract 1/4
umka21 [38]

4 1/2=4 2/4

4 2/4-1/4=4 1/4 or 4.25

8 0
3 years ago
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