I'd say that a 12 ounce feeder can feed about 40 hummingbirds
If it decreases at 4% every year, then its value becomes:
100% - 4% = 96% = 96/100 = 0.96
At the end of the 1 year its value becomes: 150*(0.96)
At the end of the 2 years its value becomes: 150*(0.96)*(0.96) = 150*(0.96)²
At the end of the 3 years its value becomes: 150*(0.96)*(0.96)*(0.96) = 150(0.96)³
So similarly at the end of 12 years, its value becomes 150*(0.96)¹²
=50*(0.96)¹² simplify with calculator.
<span>≈ 91.91
Value at the end of 12 years becomes ≈ $</span><span>91.91
I hope this helps.
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You didn't give us the sentence where the blank is placed.
Answer:
(a) No the conclusion is not justified.
b. No
c. Two defective circuits in the sample
Step-by-step explanation:
Ans: (a) No the conclusion is not justified. What is important is the percentage population of defectives;
the sample proportion is only an approximation. The population proportion
for the new process may be more than or less than that of the old process. We can decide to pick two hundred samples and discover that the number of defects is greater than the previous process
(b)
.For the defectives, the population proportion for the new process may be 0.12 or more,
although the sample of defectives is just 11 out of 100
(c) Two defective circuits in the sample. This is because the probability of having two defects from the 100n samples is less than having 11 defects
