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motikmotik
3 years ago
5

DVD cases are sold in packages of 20 padded mailing envelopes or so in packets of 12 what is the least number of cases and envel

opes you could buy so that there is one case for each envelope with none left over
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0
The least number of cases and envelopes so that there would be no remainder can be determined by finding their least common multiple. The solution is as follows

     4 | 20  12
        ---------------
        |  5     3
        -------------------

Multiplying 4*5*3 = 60. The least common multiple is 60. Thus, there should be at least 60 each of the envelopes and the packets.

Number of mailing envelopes = 20x = 60
x = 3 
Number of packets = 12y = 60
y = 5

That would be 3 packs of the envelopes, and 5 packs of the packets.


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Step-by-step explanation:

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2 years ago
The value of 4 in 3,492 is how many times the value of 4 in 704?
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3 years ago
This table represents a function plot the points to represent the function as a graph
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The graph in the attached figure N 2

Step-by-step explanation:

The complete question in the attached figure N 1

we have the ordered pairs

(-4,9),(-1,3),(0,1),(2,-3)

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Plot the given ordered pairs in the coordinate plane

Remember that

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see the attached figure

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6 0
3 years ago
Tara wants to weigh her three stuffed animals. They will only fit on the scale two at a time. Together Addie and Missy weight 18
Pepsi [2]

Answer: Addie weighs 4 ounces

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Step-by-step explanation:

Let a represent the weight of Addie.

Let m represent the weight of Missy.

Let c represent the weight of Corky.

Together Addie and Missy weigh 18 ounces. This means that

a + m = 18 - - - - - - - - - 1

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m + c = 22

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a = 4

3 0
3 years ago
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