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inessss [21]
3 years ago
7

If x to the first power is a line, and you multiply two lines together, what do you get? Think of the the exponent.

Mathematics
2 answers:
GREYUIT [131]3 years ago
8 0

Answer: A quadratic equation (also called a parabola)

Step-by-step explanation:

A line can be written as:

f(x) = a*x + c

This is a polynomial with degree 1.

Now, of we have two lines:

f(x) = a*x + c

and:

g(x) = d*x + e

And we multiply them, we will get:

f(x)*g(x) = (a*x + c)*(d*x + e) = a*d*x^2 + a*e*x + c*d*x + c*e

We can rewrite this as:

                                           = (a*d)*x^2 + (a*e + c*d)*x + (c*e)

This is a polynomial of degree = 2, this is a quadratic equation, then if you multiply two lines together, you get a quadratic equation (or a parabola)

Yakvenalex [24]3 years ago
6 0

Answer:

ax^2+ bx + c

Step-by-step explanation:

I get a parabola, that is, an equation of the second degree

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Step-by-step explanation:

if you'd look at Number One X is negative and if you look at the two number problems the x that is negative is negative for and then the one that is positive is the Y which is 3

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What special word do you use for the exponent of 2?​
alex41 [277]

Answer:

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4 0
2 years ago
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Which shows the expression below in simplified form
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Step-by-step explanation:

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3 years ago
Which sum is equal to the expression - 5x3 + 2x2 + 9x+2/<br> (x²+ 2)²
Makovka662 [10]

Answer:

Option C

Step-by-step explanation:

Given expression is \frac{-5x^3+2x^2+9x+2}{(x^2+2)^2}

Option A

\frac{A}{x^2+2}+ \frac{Bx+C}{(x^2+2)^2}

= \frac{A(x^2+2)}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}

= \frac{Ax^2+2A+Bx+C}{(x^2+2)^2}

Numerator is a quadratic polynomial, while the expression has the numerator as a cubic .

Therefore, both the expressions are not equivalent.

Option B

\frac{A}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}

= \frac{A+Bx+C}{(x^2+2)^2}

Here, numerator of the expression is a linear polynomial which is not equal to given expression.

Therefore, both the expressions are not equivalent.

Option C

\frac{Ax+B}{(x^2+2)}+ \frac{Cx+D}{(x^2+2)^2}

= \frac{(Ax+B)(x^2+2)}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}

= \frac{Ax^3+Bx^2+2Ax+2B+Cx+D}{(x^2+2)^2}

= \frac{Ax^3+Bx^2+x(2A+C)+D}{(x^2+2)^2}

Here, numerator is a cubic polynomial.

Therefore, both the expressions are equivalent.

Option D

\frac{Ax+B}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}

= \frac{x(A+C)+(B+D)}{(x^2+2)^2}

Numerator is a linear polynomial.

Therefore, sum is not equal to the given expression.

Option C will be the answer.

3 0
3 years ago
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