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IgorC [24]
3 years ago
10

Y=x + 4 and 2y = -2x - 8

Mathematics
1 answer:
Sphinxa [80]3 years ago
5 0
Socratic is a really good app for these type of questions! I definitely recommend. For science too!

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Help me with this please
meriva

Answer:

1) E

2) D

3) G

4) I

Step-by-step explanation:

1)

P = 2(l + w)

P = 2(3a + 3 + 8a - 12)

P = 2(11a - 9)

P = 22a - 18

2)

P = 22a - 18

P = 22(3) - 18

P = 66 - 18

P = 48

3)

P = a + b + c

P = 3b + 7 + 7b - 2 + 7b - 2

P = 17b + 3

4)

P = 17b + 3

P = 17(6) + 3

P = 102 + 3

P = 105

6 0
3 years ago
Pls help A bag contains 40 colored tiles. There are 12 red, 17 blue, 8 yellow and 3 green. One tile is drawn at
aleksley [76]
D blue I think, it has the most tiles in the bag 17/40 while all the other fractions are smaller decreasing their chances
4 0
3 years ago
2b^2+4b–2=0 what is the answer?
s2008m [1.1K]
2b^2+4b-2=0\\
2(b^2+2b-1)=0\\
2(b^2+2b+1-2)=0\\
2((b+1)^2-2)=0\\
2(b+1)^2-4=0\\\
2(b+1)^2=4\\\
(b+1)^2=2\\
b+1=-\sqrt2 \vee b+1=\sqrt2\\
b=-1-\sqrt2 \vee b=-1+\sqrt2


5 0
3 years ago
Find the value of x at which the function has a possible relative maximum or minimum point.​ (Recall that e Superscript x is pos
shutvik [7]

Answer:

x= -11/4 is a maximum.

Step-by-step explanation:

Remember that a function has its critical points where the derivative equal zero. Therefore we need to compute the derivative of this function and find the points where the derivative is zero. Using the chain rule and the product rule we get that

f'(x)=  -e^{-4x}(11+4x)

And then we get that   if   11+4x = 0   then   x = -11/4 . So it has a critical point at   x = -11/4.

Now, if the second derivative evaluated at that point is less than 0 then the point is a maximum and if is greater than zero the point is a minimum.

Since

f''(x) = 8e^{-4x} (5+2x)\\f''(-11/4) = -239496.56

x= -11/4 is a maximum.

6 0
3 years ago
CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU.
jonny [76]
Answer: 11 2/15
Explanation: (3+7) (1/3+4/5)
10 + 17/15
10 + 1 2/15
11 2/15
5 0
3 years ago
Read 2 more answers
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