Water is a great conductor of electricity. True or False

Physics

2 answers:

astraxan [27]3 years ago

4 0

Answer:

False

Explanation:

Think about every warning on electrical products, which is 'DO NOT KEEP NEAR WATER'

tamaranim1 [39]3 years ago

4 0

Answer:

FALSE

Explanation:

Pure water is not a good conductor of electricity. ... Because electrical current is carried by ions in solution, conductivity increases as the ion concentration increases. In such a way, that the conductivity when water dissolves ionic compounds.

You might be interested in

How many inches are in 6 meters?

blondinia [14]

There are approximately 39 inches in 6 meters.<span />

3 0

3 years ago

The magnitude of a vector can be different in different coordinate systems. The magnitude of a vector can be different in differ

Georgia [21]

Answer:

False.

Explanation:

We usually define vectors in terms of its magnitude and their orientation. Magnitude and direction does not vary with the change of a coordinate system as they are independent of coordinates and will remain the same. So it does not matter what your choice of a coordinate system is, it will not effect its direction and magnitude. However you can resolve the vector in to its components if you want.

4 0

3 years ago

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an elect

klio [65]

Complete Question

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?

Answer:

The magnetic field strength is $B= 0.0048 T$

Explanation:

The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

$\Delta V q = \frac{1}{2}mv^2$

Making v the subject

$v = \sqrt{[\frac{2 \Delta V * q }{m}] }$

Where m is the mass of electron

v is the velocity of electron

q charge on electron

$\Delta V$ is the potential difference

Substituting values

$v = \sqrt{\frac{2 * 5.9 *10^3 * 1.60218*10^{-19} }{9.10939 *10^{-31]} }$ f

$= 4.5556 *10^ {7} m/s$

For the electron to move in a circular path the magnetic force[ $F = B q v$ ] must be equal to the centripetal force[ $\frac{mv^2}{r}$ ] and this is mathematically represented as