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3 years ago

What is cumulative force?

Physics

1 answer:

Nadusha1986 [10]3 years ago

6 0

Increasing over time

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Johnson is dragging a bag on a ice surface. He pulls on the strap with a force of 112 N at an angle of 45° to the horizontal to

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Answer with Explanation:

We are given that

Force=F=112 N

$\theta=45^{\circ}$

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Time, t=3.33 minutes

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Work done, W= $Fscos\theta$

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4 years ago

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A solid sphere of uniform density has a mass of 3.0 × 104 kg and a radius of 1.0 m. What is the magnitude of the gravitational f

elena55 [62]

Answer:

a) Fg = 9.495x10⁻⁶N

b) Fg = 3.908x10⁻⁶N

$F_{g} =\frac{Gm_{1}m_{2}R }{r^{3} }$

Explanation:

Given:

m₁ = mass = 3x10⁴kg

r = radius = 1 m

m₂ = 9.3 kg

Questions:

a) What is the magnitude of the gravitational force due to the sphere located at R = 1.4 m, Fg = ?

b) What is the magnitude of the gravitational force due to the sphere located at R= 0.21 m, Fg = ?

c) Write a general expression for the magnitude of the gravitational force on the particle at a distance r ≤ 1.0 m from the center of the sphere.

a) Since R > r, the equation for the gravitational force is:

$F_{g} =\frac{Gm_{1}m_{2} }{R^{2} }$

Here,

G = gravitational constant = 6.67x10⁻¹¹m³/s² kg

Substituting values:

$F_{g} =\frac{6.67x10^{-11}*3x10^{4}*9.3 }{1.4^{2} } =9.495x10^{-6} N$

b) Since R < r, the equation for the gravitational force is:

$F_{g} =\frac{Gm_{1}m_{2}R }{r^{3} } =\frac{6.67x10^{-11}*3x10^{4}*9.3*0.21 }{1^{3} } =3.908x10^{-6} N$

c) The general expression for the magnitude of the gravitational force on the particle at a distance r ≤ 1.0 is the same to b)

$F_{g} =\frac{Gm_{1}m_{2} R}{r^{3} }$

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