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jok3333 [9.3K]
3 years ago
5

What is the milgram experiment

Physics
1 answer:
Afina-wow [57]3 years ago
5 0
The conflict between obedience to authority and personal conscience.
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How is heat converted into work in a steam engine?
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In an extremely simplified explanation,
What happens is that the steam (heat) that is generated by the burning of coal is used to rotate the motor of the steam engine.
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3 years ago
Summarize: Based on what you have learned, how will the sound that the observer hears
Reil [10]

Answer: The sound will change due to changes in frequency and the wavelength of the airplane.

Explanation: Let assume that the observer is at a stationary position. The wavelength of the sound from the airplane reduces and the frequency increases as the plane is moving toward the observer. As the airplane passes by, that is, moving away from the observer, the frequency starts to reduce while the wavelength of the sound starts to increase.

The sound that the observer hears will change base on the illustration above.

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2 years ago
A stone is thrown straight upward and reaches a maximum height of 31.8 m above its
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Answer:

aral ka muna ng mabuti para maintindihan mo

7 0
2 years ago
a train has an initial velocity of 30 m/s. If the train accelerates uniformly at a rate of 6.3 m/s ^ for 2.8 seconds what is the
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T

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the velocity is a second final to initial velocity of 39

3 0
2 years ago
A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 4.0 m/s, skat
Cerrena [4.2K]

Answer:

a)t=59.817652833125294s \approx 59.8s

b)D_1=894.01m

Explanation:

From the question we are told that

Speed of opposing player V_2=4.0m/s

First player chase his opponent aftert=2.80t

Acceleration of  first player a=0.14 m/s2

Let time of catch be  t_c

a)Generally the Equation for distance covered is mathematically given as follows

Distance to catch First opponent

D_1=\frac{1}{2}(0.14)t^2

D_1=0.07t^2

Distance to covered Second opponent

D_2=(2.8+t)*4

Generally when first opponent catch the second opponent it is represented mathematically as

D_2=D_1

0.07t^2=(2.8+t)*4

0.07t^2=11.2+4t

0.07t^2-4t-11.2

t=59.817652833125294s \approx 59.8s

b)Generally the the total time traveled by the first opponent is mathematically given as

D_1=\frac{t^2}{4}

D_1=\frac{59.8^2}{4}

D_1=894.01m

3 0
3 years ago
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