Answer:
a)
b) SSA does not constitute a proof. You need another fact.
Step-by-step explanation:
You should actually show congruency first
Angles opposite = sides are themselves equal.
<C = 50o
<J = 50o
But there is nothing that says x is 1/2 of <JAC
So it's unsolvable
Part B also has the same conclusion.
Answer:
Step-by-step explanation:
distance = = , which is approximately 5.65685
Focus on the triangle PQN and triangle SQP, prove that they are similar:
PQ=PR, PN is the altitude, so QN=NR=9
PQ of ΔSQP:QN=15:9=5:3
PS:PN=20:12=5:3
∠PQN=∠SQP (they are the same angle, reflexive property)
therefore, according to the SAS similarity theorem, ΔPQN is similar to ΔSQP
∠PNQ=∠SPQ =90 degree
therefore, QPS is a right angle.
you may have to reword it depending on what your teacher requires, column proof or paragraph proof.
If \dfrac{x-1}{3}=k 3 x−1 =kstart fraction, x, minus, 1, divided by, 3, end fraction, equals, k and k=3k=3k, equals, 3, what i
earnstyle [38]
For this case we have the following expression:
(x-1) / (3) = k
Substituting the value of k = 3 we have:
(x-1) / (3) = 3
From here, we must clear the value of x.
We have then:
x-1 = 3 * 3
x-1 = 9
x = 9 + 1
x = 10
Answer:
The value of x is given by:
x = 10