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Vlada [557]
3 years ago
8

Given f(x)=x2−2x−2, completing the square to solve for the function's zeros yields which of the following? A. (x−1)2=−2 B. (x−2)

2=4 C. (x−2)2=2 D. (x−1)2=3
Mathematics
1 answer:
LekaFEV [45]3 years ago
7 0

Answer:

(x-1)² = 3

Step-by-step explanation:

Given f(x)=x²−2x−2

Completing x²−2x−2 = 0 to square

  • x²−2x − 2=0
  • x²−2x + 1 - 3 =0
  • (x - 1)² - 3 = 0
  • (x - 1)² = 3

Correct choice is D

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Does anyone know how to do this and if so can you please help me and explain how to do it, it’ll be appreciated thank you
dalvyx [7]

Answer:

13) (5x)^{-\frac{5}{4} ⇒ \frac{1}{\sqrt[4]{(5x)^5}}

15) (10n)^{\frac{3}{2} ⇒ \sqrt{(10n)^3}

Step-by-step explanation:

Given expression:

13) (5x)^{-\frac{5}{4}

15) (10n)^{\frac{3}{2}

Write the expressions in radical form.

Solution:

For an expression with exponents as fraction like

(x)^{\frac{m}{n}

the numerator m represents the power it is raised to and the denominator n represents the nth root of the expression.

For an expression with exponents as negative  fraction like

(x)^{-\frac{m}{n}

We take the reciprocal of the term by rule for negative exponents.

So it is written as:

\frac{1}{(x)^{\frac{m}{n}}}

using the above properties we can write the given expressions in radical form.

13) (5x)^{-\frac{5}{4}

⇒ \frac{1}{(5x)^{\frac{5}{4}}}   [Using rule of negative exponents]

⇒ \frac{1}{\sqrt[4]{(5x)^5}}    [writing in radical form]

15) (10n)^{\frac{3}{2}

⇒ \sqrt{(10n)^3}     [Since 2nd root is given as \sqrt{} in radical form]

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