<span>M can have a coordinate of (-9) or (1)
There are potentially 3 different places for point M to go. It can be placed to the left of point A, between points A and B, and to the right of point B. Let's check those three possibilities.
1. Left of point A. This works if the distance between M and A is the same as the distance between A and B. So
distance between A and B = 6 - (-1.5) = 6 + 1.5 = 7.5
So the location for M would be
-1.5 - 7.5 = -9
So point M can have the value of -9.
2. Between A and B.
This would also work. Since we want a 1:2 ratio, place M one third of the way from A to B. Since we already know the distance between A and B to be 7.5, that means that we should add 7.5/3 = 2.5 to the value of A. So
-1.5 + 2.5 = 1
So point M can also have the value of 1.
3. To the right of point B
This won't work. Point B will always be closer to M than point A will be. So it's impossible to get a ratio of 1:2.</span>
Answer:
The exponential function to model the duck population is:
f(n)=415*(1.32)^n, where:
x is the duck population
n is the number of years
Step-by-step explanation:
In order to calculate the duck population you can use the formula to calculate future value:
FV=PV*(1+r)^n
FV=future value
PV=present value
r=rate
n=number of periods of time
In this case, the present value is the initial population of 415 and the rate is 32%. You can replace these values on the formula and the exponential function to model the duck population would be:
f(n)=415*(1+0.32)^n
f(n)=415*(1.32)^n, where:
x is the duck population
n is the number of years
Answer:
number 8 is a rational number because it can be written as the fraction 8/1
Step-by-step explanation:
Answer: C add 4 to both sides
I hope this helps you !
The median is 11, so 11 is part of the data set. We have an odd number of values (5) which is why the median is part of the data set.
The mode is 12. The value 12 shows up the most times. Let's say it shows up twice. So far the data set is {11, 12, 12}
Let's introduce two more numbers x and y
The new data set is {x, y, 11, 12, 12}
Add up the five values and then divide by 5. We want this result to be equal to 10
(x+y+11+12+12)/5 = 10
(x+y+35)/5 = 10
x+y+35 = 10*5
x+y+35 = 50
x+y = 50-35
x+y = 15
So we don't know what x or y is, but we know that they must add to 15. So all you have to do is list two numbers that add to 15. One such pair is x = 6 and y = 9. Another pair is x = 7 and y = 8. There are infinitely many possibilities if you can use any real number.
So one possible set is {6, 9, 11, 12, 12}
Another possible set is {7, 8, 11, 12, 12}
