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mina [271]
3 years ago
5

I need help!!!please tell me the answer!!!

Mathematics
1 answer:
Misha Larkins [42]3 years ago
4 0
Sorry wanna points bfbdjudi
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Stan made 14 of 20 free throws in basketball practice. Predict the number of free throws he would make if he attempted 100 free
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The area of an 14-cm-wide rectangle is 322 cm2. What is its length?<br> The length is<br> cm.
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Answer:

The length of rectangle is 23 cm.

Step-by-step explanation:

<u>DIAGRAM</u> :

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large{14\ cm}}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large{14\ cm}}\put(-0.5,-0.4){\bf}\put(-0.5,3.2){\bf}\put(5.3,-0.4){\bf}\put(5.3,3.2){\bf}\end{picture}

\begin{gathered}\end{gathered}

<u>SOLUTION</u> :

Here's the required formula to find the length of rectangle :

{\longrightarrow{\pmb{\sf{A_{(Rectangle)}  = l \times b}}}}

  • A = Area
  • l = length
  • b = breadth

Substituting all the given values in the formula to find the length of rectangle :

\begin{gathered}\qquad{\longrightarrow{\sf{A_{(Rectangle)}  = l \times b}}}\\\\\qquad{\longrightarrow{\sf{322 = l \times 14}}}\\\\\qquad{\longrightarrow{\sf{322 = 14l}}}\\\\\qquad{\longrightarrow{\sf{l =  \dfrac{322}{14}}}}\\\\\qquad{\longrightarrow{\sf{l =  \cancel{\dfrac{322}{14}}}}}\\\\\qquad{\longrightarrow{\sf{l = 23 \: cm}}}\\\\\qquad{\star{\underline{\boxed{\sf{ \pink{l = 23 \: cm}}}}}}\end{gathered}

Hence, the length of rectangle is 23 cm.

\begin{gathered}\end{gathered}

<u>LEARN</u><u> </u><u>MORE</u> :

\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}

\rule{300}{2.5}

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