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SVEN [57.7K]
3 years ago
13

It takes 3/5 feet of ribbon to make a pin. You have 9 feet of ribbon. How many pins can you make?

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0
You can divide 9 by \frac{3}{5} to find the amount of pins, (let's call this number x), you can make with 9 $ ft$ of ribbon.

x=9 \div \frac{3}{5} \\ \\  x= \frac{9}{1} \div \frac{3}{5} \\ \\ x= \frac{9}{1} \times \frac{5}{3} \\ \\ x= \frac{9 \times 5}{1 \times 3} \\ \\ x= \frac{45}{3} \\ \\ x=15

So, 15 pins can be made.


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A local company makes a candy that is supposed to weigh 1.00 ounces. A random sample of 25 pieces of candy produces a mean of 0.
AysviL [449]

Answer:

n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107

So the answer for this case would be n=107 rounded up to the nearest integer

Step-by-step explanation:

Information given

\bar X= 0.996 the sample mean

s=0.004 the sample deviation

n =25 the sample size

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.001 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

We can use as estimator of the real population deviation the sample deviation for this case \hat \sigma = s/ The critical value for 99% of confidence interval is given by z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107

So the answer for this case would be n=107 rounded up to the nearest integer

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3 years ago
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artcher [175]

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