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lesya692 [45]
3 years ago
13

Find the distance between the points (-9,2) and (-1,4). Round to the nearest tenth if necessary.

Mathematics
1 answer:
AlekseyPX3 years ago
8 0

Answer:

The answer to the nearest tenth is 8.2

Step-by-step explanation:

In order to find the distance between any two points, you must use the distance formula. when you plug in the points into the formula you end up with 8.246, rounded to the nearest tenth would be 8.2. I hope this helps!

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Two telephone calls come into a switchboard at random times in a fixed one-hour period. Assume that the calls are made independe
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Answer:

0.25

Step-by-step explanation:

From the given information:

Since the times are uniform distributed over the one hour period (0,1):

Then;

f_1(y_1) = 1

f_2(y_2) = 1

So, Y_1 and Y_2 are independent; then:

f(y_1|y_2) = f_1(y_1)f_2(y_2)  \\ \\ = 1(1) = 1

P(Y_1\le 0.5 Y_2 \le 0.5) = \int ^{0.5}_{0} \int ^{0.5}_{0} f(y_1,y_2) dy_{2}dy_{1}

\implies  \int ^{0.5}_{0} \int ^{0.5}_{0} (1)  dy_{2}dy_{1}

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3 0
2 years ago
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

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