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3 years ago

How do you work this problem

Mathematics

1 answer:

ankoles [38]3 years ago

7 0

An easy way is to do it, if you get confused by multiplying fractions, is by turning the fractions into decimals. Since you are trying to find N you want to multiply the 1/5 by the 1/3.

1/5 = 0.2

1/3 = 0.33333333333333333333333333333333

if you multiply those you get 0.06666666666666666666666666666667 which when put into a fraction it equals 1/15

but if you don't want to do that just try to remember that you want to get by itself. and when multiplying fractions in this situation the bottom numbers only matter.. so 5 x 3 = 15 1/15

would you like me to put it in a document to show you?

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Sam and Bobby want to know who cycled faster. The table shows the total miles Sam traveled over time. The graph shows the same r

tigry1 [53]

Answer:

<h2>Sam cycled fast, at a rate of 10 miles per hour.</h2>

Step-by-step explanation:

To solve this problem we have to find the slope of each case. The definition of a slope is:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\$

Where $(x_{1};y_{1})$ is the first point, and $(x_{2};y_{2})$ is the second point.

Let's find each slope.

Let's use the points $(2;20)$ and $(5;50)$

Applying the definition of the slope, we have:

$m_{sam} =\frac{50-20}{5-2}=\frac{30 \ miles}{3 \ hour}=10 \ miles/hour$

This relation means that Sam cycled 10 miles per hour.

<h3>Bobby.</h3>

Let's use the points $(2;18)$ and $(6;54)$

$m=\frac{54-18}{6-2}=\frac{36 \ miles}{4 \ hour}=9 \ miles/hour$

Bobby cycled 9 miles per hour.

Therefore, according to these ratios, Sam cycled fast, at a rate of 10 miles per hour.

7 0

2 years ago

Ryan starts saving money to buy a car right after his 16th birthday. He already has $120 from his birthday. After 3 months he ha

nlexa [21]

Remark

The basic equation is y = mx + b

y = the total amount of money

m = The amount of money he save each month (it is a constant).

b = the y intercept which is his starting amount or 120 dollars.

x = the number of months (this is a variable).

After 3 months he has 840 dollars. That's y

840 = 3*m + 120 Subtract 120 from both sides

840 - 120 = 3m

720 = 3m

240 = m So he saves 240 every month.

Now the equation becomes.

y = 240 * x + 120

Savings after 24 months

y = Total

m = 240 dollars/month

x = 24 months

b = 120

y = 24*240 + 120

y = 5760 + 120

y = 5580

He had 5580 dollars after saving for 2 years (or 24 months total) This assumes that when he started, he took his birthday money and added a 1 month payment to it

5 0

2 years ago

-6/5k=12 what is k? please explain

pentagon [3]

Answer:.......

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone help me with these math questions?

maw [93]

Answer:

1. SAS POSTULATE

2. ASA POSTULATE

3. SAS POSTULATE

4. SSS POSTULATE

5. SSA POSTULATE

6. AAS POSTULATE

8 0

2 years ago

Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t

MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6. $\overline 6$

Given that 6. $\overline 6$ > 0, we have;

At the maximum volume, the width of the block, w = 6. $\overline 6$ cm ≈ 6.7 cm

The maximum volume, $V_{max}$ , is therefore given when w = 6. $\overline 6$ cm = 20/3 cm as follows;

V = 10·w² - w³

$V_{max}$ = 10·(20/3)² - (20/3)³ = 4000/27 = 148. $\overline {148}$

The maximum volume, $V_{max}$ = 148. $\overline {148}$ cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0

2 years ago