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3 years ago

PLEASE HELP ME OKT I DONT UNDERSTAND

Mathematics

1 answer:

Nostrana [21]3 years ago

4 0

Answer:

See below.

Step-by-step explanation:

5a)

In an isosceles triangle, the angles opposite the congruent sides are congruent.

m<A = 40 deg

m<B = 40 deg

m<A + m<B + m<C = 180

40 + 40 + m<C = 180

m<C = 100 deg

5b)

In a right triangle, one angle is a right angle.

m<A = 40 deg

m<B = 90 deg

m<A + m<B + m<C = 180

40 + 90 + m<C = 180

m<C = 50 deg

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In ABC, m A) 180 B) 29 C) 6 D) 122

vivado [14]

None of the above its actually number 22
Hope that helped!?
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4 0

4 years ago

How do you solve this and what is the answer?

Pachacha [2.7K]

Answer:

Step-by-step explanation:

∠ABC = 1/2 ∠AOC

since we know ABC = 30° we can solve for AOC with a bit of Algebra

30 = 1/2 AOC

60 ° = AOC

:) does it make sense?

the formula about is for inscribed angles , that is an angle that touches the outside of the circle and then goes through the other side. :) Like ∠ABC

4 0

3 years ago

Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5

lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer: v = 5v + 4u + 1.5sin(3t),

1.5sin(3t)

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1

v represents the "velocity function" i.e v = u'(t)

As v = u'(t)

u' = v

since u' = v

v' = u"

v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )

= 5v + 4u + 1.5sin(3t) ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ = $\left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]$ $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]$