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jeyben [28]
3 years ago
10

Find the 20th term of the sequence. 1600, 1200, 900, ...

Mathematics
1 answer:
alukav5142 [94]3 years ago
6 0

First approach :

The above series can be seen as

1600 , (1600–400) 1200, (1200–300) 900 .

So we see that the values are getting decreased by 400,300 respectively.

Hence the next term in the sequence will be 900–200 = 700.

Other approach could be :

A geometric progression with ratio as 3/4.

1600*(3/4) = 1200

1200*(3/4) = 900

900*(3/4) = 675

Taking the above two approaches in mind,the two possible answers could be 700 or 675

Um- here ya go

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One of the roots of the quadratic equation 4mnx^2 – 6m^2x – 6n^2x + 9mn = 0 (m, n ≠ 0) is a)-3m/2n b)3m/2n c)2m/3n d)-2m/3n
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B.\ \frac{3m}{2n}

Step-by-step explanation:

Given

4mnx^2 - 6m^2x - 6n^2x + 9mn = 0\ (m, n \neq  0)

Required

Calculate one of the root of the equation

4mnx^2 - 6m^2x - 6n^2x + 9mn = 0

Factorize

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Make x the subject of formula in both expressions

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x = \frac{3n}{2m}\ or\ x = \frac{3m}{2n}

<em>From the list of given options, one of the roots of the equation is</em> \frac{3m}{2n}

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