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3 years ago

Plz help will mark brainliest

Mathematics

2 answers:

levacccp [35]3 years ago

7 0

Answer:

-2

Step-by-step explanation:

$-2^{2}-3(-2)-10 \\4+6-10\\10-10\\0$

$5^{2} -3(5)-10\\25-15-10\\10-10\\0$

MariettaO [177]3 years ago

5 0

X = -2 and x = 5 are the correct answers

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The two pictures are the questions and question five is what i need help with.

Mama L [17]

Answer:yes they do

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the first term, a1, of an arithmetic sequence if a12 = 38 and a45 = 170.

snow_lady [41]

Standard formula for arithmetic sequence:
an = a0 + d(n-1)

if we use the two terms given, setting a12 as starting term and a45 as the end term an.

170 = 38 + 33d
170 - 38 = 33d
132 = 33d

132/33 = d
This is the common difference, use it to find the first term.

38 = a0 + (132/33)(12-1)
38 = a0 + (132/33)(11)
38 = a0 + 132/3
38 - 132/3 = a0
38 - 44 = a0
-6 = a0

The starting term is -6

8 0

3 years ago

The residents of a certain dormitory have collected the following data: People who live in the dorm can be classified as either

Ad libitum [116K]

Answer:

The steady state proportion for the U (uninvolved) fraction is 0.4.

Step-by-step explanation:

This can be modeled as a Markov chain, with two states:

U: uninvolved

M: matched

The transitions probability matrix is:

$\begin{pmatrix} &U&M\\U&0.85&0.15\\M&0.10&0.90\end{pmatrix}$

The steady state is that satisfies this product of matrixs:

$[\pi] \cdot [P]=[\pi]$

being π the matrix of steady-state proportions and P the transition matrix.

If we multiply, we have:

$(\pi_U,\pi_M)*\begin{pmatrix}0.85&0.15\\0.10&0.90\end{pmatrix}=(\pi_U,\pi_M)$

Now we have to solve this equations

$0.85\pi_U+0.10\pi_M=\pi_U\\\\0.15\pi_U+0.90\pi_M=\pi_M$

We choose one of the equations and solve:

$0.85\pi_U+0.10\pi_M=\pi_U\\\\\pi_M=((1-0.85)/0.10)\pi_U=1.5\pi_U\\\\\\\pi_M+\pi_U=1\\\\1.5\pi_U+\pi_U=1\\\\\pi_U=1/2.5=0.4 \\\\ \pi_M=1.5\pi_U=1.5*0.4=0.6$

Then, the steady state proportion for the U (uninvolved) fraction is 0.4.

4 0

3 years ago

WILL MARK YOU BRAINLIEST

slega [8]

Answer:

i need more details then this its not really explaining anything

Step-by-step explanation:

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3 years ago

What shape would have a cross section that could match that of a sphere?

lapo4ka [179]

Cross sections of spheres are cicles. Therefore, if cut parallel to the ends, CYLINDER also has cross sections that match that of a circle.

3 0

3 years ago