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masha68 [24]
4 years ago
7

A car approaches you with its horn blowing. The observed frequency is 503.7 Hz. Assume the speed of sound is 1100 ft/s. The car'

s horn has a frequency of 450 Hz. How fast is the car going? Express your answer in mph.
1420

79.8

117
Physics
1 answer:
vladimir2022 [97]4 years ago
6 0

Answer

79.8 miles per hours fast is the car going.

Formula

By using the dopplers effect. (When source is approching .)

f_{observed} = f_{source}(\frac{v}{v - v_{source}} )

As given

A car approaches you with its horn blowing.

The observed frequency is 503.7 Hz.

The speed of sound is 1100 ft/s .

The car's horn has a frequency of 450 Hz.

i.e

f_{observed} = 503.7 Hz

v = 1100 ft/s

f_{source} = 450 Hz

Put in the above formula

503.7= 450\times \frac{1100}{1100 - v_{source}}

503.7\times {1100 - v_{source}=450\times 1100

554070- 503.7v_{source}=495000

554070-495000=503.7v_{source}

59070=503.7v_{source}

v_{source}= \frac{59070}{503.7}

v_{source}= 117.3\ ft\ per\ s(Approx)

Now convert 117.3 ft per second into miles per hours.

1\ foot = \frac{1}{5280}\ miles

1\ hours = \frac{1}{3600}\ hours

\frac{117.3\ feet}{second} = \frac{117.3\times \frac{1}{5280}\ miles}{\frac{1}{3600}\ hours}

\frac{117.3\ feet}{second} = \frac{0.022216\ (Approx)}{0.00028\ (Approx)}

117.3 feet per second = 79.8 miles per hours (Approx)

Thus

v_{source}= 79.8\ miles\ per\ hours

Therefore the 79.8 miles per hours fast is the car going.

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Explanation:

Lets explain how to solve the problem

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<em>The effect would be is the frictional force must be increase</em>

<em></em>

<em>If the frictional force does not increase the wagon will accelerate</em>

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