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Llana [10]
3 years ago
11

Which particle is commonly used to initiate a fission chain reaction

Physics
1 answer:
Snezhnost [94]3 years ago
5 0
Neutron is commonly used to initiate a fission chain reaction.
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What are the benefits and dangers of visual light waves
Anton [14]

Blue-violet light on the visible light spectrum can cause damage to retina cells, increasing one's risk of developing age-related macular degeneration, explains Essilor.


5 0
3 years ago
What kind of wave (transverse of longitudinal) is each of the following and why?
Elina [12.6K]

Answer:

1.) Longitudinal waves

2.) Transverse waves

3.) Longitudinal waves

Explanation:

The sound of one whale calling another whale underwater.  is a longitudinal wave since the medium, in this case the body of water, is vibrating parallel to the direction of propagation of the wave.

A pulse sent down a stretched rope by snapping one end of it. ( transverse wave) because its oscillations are perpendicular to the direction of the wave or path of propagation

The vibrations in a guitar string

Longitudinal wave. Because its oscillations are parallel to the direction of the wave or path of propagation

5 0
4 years ago
A tradesman sharpens a knife by pushing it with a constant force against the rim of a grindstone. The 30-cm-diameter stone is sp
Lorico [155]

Answer:

a. 0.21 rad/s2

b. 2.205 N

Explanation:

We convert from rpm to rad/s knowing that each revolution has 2π radians and each minute is 60 seconds

200 rpm = 200 * 2π / 60 = 21 rad/s

180 rpm = 180 * 2π / 60 = 18.85 rad/s

r = d/2 = 30cm / 2 = 15 cm = 0.15 m

a)So if the angular speed decreases steadily (at a constant rate) from 21 rad/s to 18.85 rad/s within 10s then the angular acceleration is

\alpha = \frac{\Delta \omega}{\Delta t} = \frac{21 - 18.85}{10} = 0.21 rad/s^2

b) Assume the grind stone is a solid disk, its moment of inertia is

I = mR^2/2

Where m = 28 kg is the disk mass and R = 0.15 m is the radius of the disk.

I = 28*0.15^2/2 = 0.315 kgm^2

So the friction torque is

T_f = I\alpha = 0.315*0.21 = 0.06615 Nm

The friction force is

F_f = T_f/R = 0.06615 / 0.15 = 0.441 N

Since the friction coefficient is 0.2, we can calculate the normal force that is used to press the knife against the stone

N = F_f/\mu = 0.441/0.2 = 2.205 N

7 0
3 years ago
Light shines through a single slit whose width is 5.7 x 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a
lilavasa [31]

Answer:

\lambda = 570\ nm

Explanation:

Given,

Width of slit, W = 5.7 x 10⁻⁴ m

Distance between central bright fringe, L = 4 m

distance between central bright fringe and first dark fringe, y = 4 mm

Diffraction angle

tan \theta = \dfrac{y}{L}

tan \theta = \dfrac{4}{4\times 10^3}

\theta = 0.0572

Now.

W sin \theta = m \lambda

m = 1

5.7 \times 10^{-4} \times sin (0.0572) = 1 \times \lambda

\lambda = 569.99 \times 10^{-9}\ m

\lambda = 570\ nm

4 0
3 years ago
A student wants to determine the effect of mass on kinetic energy. She will drop two balls of the same size into a pool of water
Anastasy [175]

Answer:

She should drop two balls with different masses from the same height

Explanation:

4 0
2 years ago
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