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meriva
3 years ago
9

The Eiffel Tower in Paris, France. Lizbeth is 5.5 feet tall. She looks up at an angle of elevation of 72° to see the top from 31

8 feet away. Based on her measurements, calculate the height of the Eiffel Tower. Round to the nearest hundredth of a foot.
Mathematics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

The height of the Eiffel Tower will be 318 feet.

Step-by-step explanation:

Please check the attached graph.

From the diagram, it is clear that Lizbeth is 5.5 ft tall, seeing the top from 318 feet away, making an angle of elevation to be 72⁰.

The diagram makes a right-angled triangle.

  • Given the angle = Ф = 72⁰
  • Adjacent = a = 5.5 ft
  • Opposite = b = 318 ft
  • Hypotenuse = the height of the Eiffel Tower = c ?

Pythagorean Theorem:

For a right-angled triangle, with sides 'a' and 'b', the hypotenuse 'c' is defined as:

c=\sqrt{a^2+b^2}

  • a=5.5
  • b=318

c=\sqrt{5.5^2+318^2}

c=318 feet

Therefore, the height of the Eiffel Tower will be 318 feet.

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eric is 70 inches tall pablo is as half as tall as eric annette is 5.25 inches taller than pablo how tall is annette
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Answer:

40.25 inches

Step-by-step explanation:

Following what the problem mentions:

"eric is 70 inches tall"

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Enter the lengths of QS and TV<br><br>QS=<br>TV=​
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Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
3 years ago
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