5c^3(c^2 + 12c + 36) --> 5c^3(c+6)(c+6) --> 5c^3(c+6)^2
Answer:
A
-2 < x ≤ 3 (All x values between -2 and 3; excluding -2 and including 3)
Step-by-step explanation:
I feel the answer is A because from what we know, domain is the x-intercept or x. So both C and D are not the answer because the y-intercept is not the domain, the y-intercept is the range. Next I looked at both A and B, well, if you look closely answer choice A says "excluding -2 and including 3" and choice B says "including -2 and excluding 3". I also seen on the graph that the point of (3,3) has a filled in dot and the point at (-2,-1) has an opened dot. A filled in dot always means you either have a ≥ (greater than or equal to sign) or a ≤ (less than or equal to sign). While an opened dot always means you just have < (greater than) or a > (less than) sign. So the correct answer is A!! Hope you have a fantastic rest of your day! :)))
Answer:
Sale Price: 276.25
Step-by-step explanation:
The original price of the item is $325 and the markdown is 15% off.
So, all you have to do is find out what 15% of $325, which it's 48.75, and subtract that from $325 to get your final sale price, which is $276.25.
Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
Answer:
Step-by-step explanation:
She ran on 2 weekends.
<u>We need to add:</u>
<u>Solve:</u>
- 2 + 3 = 5
- = 4/5 + 1/5 = 1
- = 5 + 1
- = 6.
Alexandra ran 6 miles in total.