Ashley bought 6 yds of ribbon for $5.28. What ratio is proportional to this?
2 answers:
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Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
is the linear equation to find the temperature T at an elevation x on the mountain, where x is in thousands of feet.
<em><u>Solution:</u></em>
The linear equation in slope intercept form is given as:
T = cx + k ------ (i)
Where "t" is the temperature at an elevation x
And x is in thousands of feet
<em><u>Given that its 76 degrees fahrenheit at the 6000-foot level of a mountain</u></em>
Given, when c = 6 thousand ft and fahrenheit
This implies,
From (i)
76 = c(6) + k
76 = 6c + k
⇒ k = 76 - 6c ----- (ii)
<em><u>Given that 49 degrees Fahrenheit at the 12000-foot level of the mountain</u></em>
Given, when c = 12 thousand ft and fahrenheit
This implies,
From (i)
49 = c(12) + k
49 = 12c + k
Substitute (ii) in above equation
49 = 12c + (76 - 6c)
49 = 12c + 76 - 6c
49 - 76 = 6c
6c = -27
Substituting the value of c in (ii) we get
Substituting the value of c and k in (i)
Where "x" is in thousands of feet
Thus the required linear equation is found