Ashley bought 6 yds of ribbon for $5.28. What ratio is proportional to this?

Mathematics

2 answers:

lara31 [8.8K]3 years ago

6 0

My best guest would be A.

guajiro [1.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

the answer is c

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A culture started with 5000 bacteria after 5 hours it grew to 6500 bacteria predict how many bacteria will be present after 16 h

postnew [5]

Answer:

After 16 hours bacterial count will be 11600.

Step-by-step explanation:

Bacterial growth is always an exponential growth in a given culture.So the formula for the growth will be

Final counts of bacteria = Initial counts × $(rate of growth)^{time}$

Given from first part Initial counts = 5000

Final counts= 6500 and time of growth = 5 hours

Then we will get the value of rate of growth of bacteria from the bacteria

⇒ 6500 = 5000× $(rate)^{5}$

$(rate)^{5}= \frac{6500}{5000} = 1.3$

$Rate = \sqrt[5]{1.3} = 1.05$

Now again to get the value of bacteria after 16 hours

Final Count = 5000× $(1.05)^{16}$

= 5000×2.32

= 11600

7 0

4 years ago

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balandron [24]

Answer:

The number of years it will take for Yasemin's account balance to reach $1500 is 13.52 years.

Step-by-step explanation:

Where the model of the relationship between the time, t, in years, since the account was first opened and the and the balance in Yasemin's account is presented as follows;

$B(t) = 1000 \times e^{(0.03 \times t)}$

To find find out how many years it will take for Yasemin's account balance to reach $1500, we substitute B(t) = $1500 since we are told that after the years his account balance became $1500 as follows;

$\$ 1500 = 1000 \times e^{(0.03 \times t)}$

We now solve for t

$\$ 1500 = 1000 \times e^{(0.03 \times t)}\\\\\frac{1500 }{1000 } = e^{(0.03 \times t)}\\1.5 = e^{(0.03 \times t)}\\\\ln(1.5) = ln (e^{(0.03 \times t)})\\\\ln(1.5) = (0.03 \times t) \times ln (e)\\\\\therefore ln(1.5) = (0.03 \times t) \\\\t = \frac{ln(1.5)}{0.03 } = 13.52 \ years$