Find the 10th term of 3, 9 /2 , 27/4
1 answer:
Answer:
Step-by-step explanation:
the nth term of a geometric sequence is
∙
x
a
n
=
a
r
n
−
1
where a is the first term and r the common ratio
r
=
a
2
a
1
=
a
3
a
2
=
...
...
=
a
n
a
n
−
1
here
a
=
3
and
r
=
9
3
=
27
9
=
3
⇒
a
10
=
3
×
3
9
=
3
10
=
59049
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