Given: <span>y = x^2 + 6x - 5. Then a = 1, b = 6 and c = -5.
The x-coord. of the vertex is given by x = -b / (2a), which here is x = -6 / (2*1) = -3.
Use the given formula </span><span>y = x^2 + 6x - 5 to find the value of y when x = -3:
y = (-3)^2 + 6(-3) - 5 = 9 - 18 - 5 = -14
Then the vertex is (-3, -14).</span>
Hi Dezariaspencer
All we have to do is simply add 2x to both sides and we have our answer.
Answer: y = 11 + 2x.
Thank you for asking your question, have a good day.
Answer:
If PQRS is a parallelogram with two adjacent congruent sides, then it must be a rhombus. A rhombus is a parallelogram characterized by having all sides congruent. Therefore, the adjacent sides must be congruent as well.
Y = 180 - 52 - 59 = 69 degrees . . . . . . . . (angles on a straight line are supplementary, i.e. add up to 180 degrees)
x = 180 - 69 - 63 = 48 degrees . . . . . . . . (sum of interior angles of a triangle is 180 degrees)
Therefore, m/_x = 48 degrees.
