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Lelu [443]
3 years ago
13

9- Un auto Recorre 500m en 4 segundos, calcula la velocidad promedio.

Physics
1 answer:
Brut [27]3 years ago
7 0

Answer:

Is this Spanish?

Explanation:

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If 53.62 ml of an oil weighs 48.34 g what is the specific gravity of the oil
Maksim231197 [3]
The specific gravity is the ratio of the density of oil to the density of water. Since the density of water is 1g/ml, the density of a substance is numerically the same as the specific gravity.

However, specific gravity is a dimensionless number, while density has units mass/volume.

So, the density of oil is .901 g/ml, but the specific gravity is just .901

In Imperial units, the density of the oil is 56.2 lb/ft^3, but the specific gravity is still .901
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3 years ago
How do bubbles form in water​
Katen [24]

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I'm pretty sure it has something to do with air

Explanation:

4 0
3 years ago
•• Your roommate is working on his bicycle and has the bike upside down. He spins the 60-cm-diameter wheel, and you notice that
Y_Kistochka [10]

Answer:

v=0.57\frac{m}{s}

a_c=10.83\frac{m}{s^2}

Explanation:

We have an uniform circular motion, therefore, the pebble’s speed is given by the distance traveled in a revolution (2\pi r) and the period (T), since this is the time pebble’s takes to complete a revolution:

v=\frac{2\pi r}{T}

The period is inversely proportional to the frequency:

T=\frac{1}{f}

So, we have:

v=\frac{2\pi r}{\frac{1}{f}}\\v=2\pi rf\\

Recall that the radius is the half of the diameter and one revolution per is equal to one Hz:

v=2\pi (30*10^{-2}m)(3Hz)\\v=0.57\frac{m}{s}

The centripetal acceleration is defined as:

a_c=\frac{v^2}{r}\\a_c=\frac{(0.57\frac{m}{s})^2}{30*10^{-2}m}\\\\a_c=10.83\frac{m}{s^2}

6 0
3 years ago
Can anyone help fill out the table?
navik [9.2K]
Answer:


What table I don’t see any table
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4 years ago
What is the best example of the purpose of scientific notation?
Gemiola [76]

The correct answer would be to express large and small numbers.


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3 years ago
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