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Alenkinab [10]
3 years ago
13

Name a 2 digit odd number that is prime. Name a 2 digit odd number that is composite .

Mathematics
1 answer:
salantis [7]3 years ago
8 0
11 for the first one and 12 for the second one
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(<br> x<br> −<br> 3<br> )<br> (<br> x<br> −<br> 1<br> )<br> (x−3)(x−1)
galina1969 [7]

Answer:

x² - 4x + 3

Step-by-step explanation:

When multiplying binomials (two terms in an expression), use FOIL. It stands for the first, outside, inside, and last terms in each bracket.

(x−3)(x−1)           Expand with FOIL

= x² - x - 3x + 3      Collect like terms

= x² - 4x + 3

7 0
3 years ago
An equilateral triangle has a perimeter of 48 cm. What is the area?
KiRa [710]

Answer:

A=64\sqrt{3}\ cm^2

Step-by-step explanation:

we know that

An <u><em>equilateral triangle</em></u> has three equal sides and three equal interior angles (each interior angle measure 60 degrees)

so

The perimeter is equal to

P=3b

where

b is the length side of the equilateral triangle

we have

P=48\ cm

substitute

48=3b

solve for b

b=48/3\\b=16\ cm

Find the area

The formula of area applying the law of sines is equal to

A=\frac{1}{2}b^2sin(60^o)

substitute the value of b

A=\frac{1}{2}(16)^2sin(60^o)

sin(60^o)=\frac{\sqrt{3}}{2}

A=\frac{1}{2}(16)^2(\frac{\sqrt{3}}{2})

A=64\sqrt{3}\ cm^2

6 0
3 years ago
Please help. The numerator is an x
Sati [7]

Answer:

x = 30

Step-by-step explanation:

\frac{x}{6} +1=6\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\\frac{x}{6}+1-1=6-1\\\\Simplify\\\frac{x}{6}=5\\\\\mathrm{Multiply\:both\:sides\:by\:}6\\\frac{6x}{6}=5\times\:6\\\\Simplify\\x=30

7 0
3 years ago
I need help! Math question
iren2701 [21]
Again, a spreadsheet or suitable calculator makes this short work.

The sum is 184.

_____
The terms being summed are ...
  2·3² +3 = 2·9 +3 = 18 +3 = 21
  2·4² +3 = 35
  2·5² +3 = 53
  2·6² +3 = 75
Their total is
  21 +35 +53 +75 = 184

8 0
3 years ago
Make t as the subject!! HELP MEE
Umnica [9.8K]

Answer:

t = (p^2/mn) - 1/n

Step-by-step explanation:

Here, we want to make t the subject of the formula

we start by equating both sides so as to remove the root

we have this as;

m(t + n)/t = p^2

m(t + n) = tp^2

mt + mn = tp^2

mn = tp^2 - mt

mn = t(p^2-m)

t = (p^2 - m)/mn

t = p^2/mn - 1/n

6 0
3 years ago
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