Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
It makes everything clear from a mathematical point , much easier to solve the question in equation form than trying to figure it out from a long word problem
Answer:
1.A,B,C,D
2. AB, CD
3. AC, BD
4. Line AD (don't take my word for this one)
Step-by-step explanation:
Is the question asking what is the product(end value) of 2x3 +3.4y when x=3 and y=4?
Answer:
k = 54
Step-by-step explanation:
1. Multiply 6 time 9. This is the only step to get the answer.
6 × 9 = 54
k = 54
2. (Option step) To check your answer plug in 54 for k in the equation and divide it by 9. Your result should be 6.
54 ÷ 9 = 6
