I have solved this problem in given picture
At n = 2
a₂ = (-1)² + 3a₂₋₁ + 2
a₂ = 1 + 3a₁ + 2
a₂ = 1 + (3)(5) + 2
a₂ = 18
At n = 3
a₃ = (-1)³ + 3a₃₋₁ + 2
a₃ = -1 + 3a₂ + 2
a₃ = -1 + (3)(18) + 2
a₃ = 55
At n = 4
a₄ = (-1)⁴ + 3a₄₋₁ + 2
a₄ = 1 + 3a₃ + 2
a₄ = 1 + (3)(55) + 2
a₄ = 168
The first four terms are 5, 18, 55, 168
Answer:
A, E and D
Step-by-step explanation:
Answer:
i have the same question... im on the same one... i cant find out the answer, let me know when you find it out please
Step-by-step explanation: