3 years ago

Can you identify a sample from a living organism by examining it under a microscope? Yes or No

Chemistry

1 answer:

Ghella [55]3 years ago

6 0

Vguttfvjhhutdxcbhyyyhhhhhhh HD jv bc HD g G G HD F G G f ft

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Deep sea divers can experience the bends due to an increased amount of nitrogen in the blood

garri49 [273]

b is the correct answer

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4 years ago

Is soda an acid or a base

Aneli [31]

Answer:

It's an Acid

Explanation:

cuz of the Co2 and it's naturally acidic nature

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3 years ago

Marco put a pot of water on to boil eggs. After a few minutes, all the water was gone. This is an example of ___.

kvv77 [185]

Answer:

evaporation

Explanation:

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3 years ago

Which are exmaples of chemical change?

aniked [119]

Answer:

C: salt is dissolved into freshwater

D: salt is dissolved into freshwater

F: frying changes the color and texture of an egg

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3 years ago

two objects each have a mass of 5.0 g. one had a density of 2.7 g. and the other has a density of 8.4 g. which object has a larg

gulaghasi [49]

Answer:

The body with 2.7 $\frac{g}{(cm^3)}$ has a larger volume

Explanation:

There is a missespelling in the question. The units of density cannot be g, they usually are $\frac{g}{(cm^3)}$

In order to answer this question, we need to use the formula of the density of a body:

$Density = \frac{Mass}{Volume} = \frac{M}{V}$

For body A:

Mass (M) = 5.0 g

Density (D) = 2.7 $\frac{g}{(cm^3)}$

2.7 $\frac{g}{(cm^3)}$ = 5g * 1/V

V1 = 5g / (2.7 $\frac{g}{(cm^3)}$ )

V1 = 1.85 $1.85 cm^3$

For Body B:

Mass (M) = 5.0 g

Density (D) = 8.4 $\frac{g}{(cm^3)}$

8.4 $\frac{g}{(cm^3)}$ = 5g * 1/V

V2 = 5g / (8.4 $\frac{g}{(cm^3)}$ )

V2 = 0.59 $1.85 cm^3$

So V1 is bigger than V2

5 0

3 years ago