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loris [4]
3 years ago
5

What is true about both sodium and gold?

Chemistry
2 answers:
fomenos3 years ago
8 0
D)They are metals.
_________________
Vlada [557]3 years ago
4 0
Generally speaking, gold<span> is not very </span><span>reactive, whereas sodium is highly reactive. They are most definitely not in the same group since sodium is in group 1 and Gold is in group 11. Gold is indeed a transition metal so my best guess would be D. </span>
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Which elements in the periodic table are metalloids or have semimetallic properties
Marysya12 [62]
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8 0
4 years ago
If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.
kicyunya [14]
Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

CH_{3}COOH \ \textless \ ---\ \textgreater \   H^{+} + CH_{3}COO^{-}

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

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The change in Concentration Δ [CH_{3}COOH]= 0.001 moldm^{-3}


                                  CH3COOH          H+           CH3COOH    
Initial  moldm^{-3}                      x           0                     0
                                                                                                                       
Change moldm^{-3}        -0.001            +0.001           +0.001
                                                                                                       
Equilibrium moldm^{-3}      x- 0.001      0.001             0.001
                                                                              

Since the k_{a} value is so small, the assumption 
[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium} can be made.

k_{a} = [tex]= 1.8*10^{-5}  =  \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} =  \frac{0.001^{2}}{x}

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

         2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps! 



8 0
3 years ago
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frozen [14]
Is 2.0 x 10 to the -9th power an option
5 0
3 years ago
The water for the pan is not saturated with co2. will the reported percent caco3 in the original sample be too high, too low, or
enot [183]

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8 0
4 years ago
The speed of light in a vacuum is 2.998 x 108 m/s. How long does it take for light to circumnavigate the Earth, which has a circ
Luba_88 [7]

Answer:

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Explanation:

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Therefore,

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24900 mile = 4.01×10⁷ m

Finally, we shall determine the time taken for light to circumnavigate the Earth, this can be obtained as follow:

Distance = 4.01×10⁷ m

Speed = 2.998×10⁸ m/s

Time =?

Speed = distance / time

2.998×10⁸ = 4.01×10⁷ / time

Cross multiply

2.998×10⁸ × time = 4.01×10⁷

Divide both side by 2.998×10⁸

Time = 4.01×10⁷ / 2.998×10⁸

Time = 0.13 s

Thus, it will take 0.13 s for light to circumnavigate the Earth.

5 0
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