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Ne4ueva [31]
3 years ago
15

What is the chemical equation for methamphetamine ​

Chemistry
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

C10H15N is the chemical equation for methamphetamine

Sonja [21]3 years ago
6 0
The chemical formula for methamphetamine or meth is C10H15N
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The moon's craters are remnants of meteorite collisions. suppose a fairly large asteroid that has a mass of 5.00×10^12 kg (about
Paul [167]

<u>Given:</u>

Mass of asteroid, M1 = 5.00*10¹² kg

Velocity of asteroid V1 = 15.0 km/s

Mass of moon, M2 = 7.36*10²² kg

<u>To determine:</u>

The recoil velocity of moon, V2

<u>Explanation:</u>

Since the collision is perfectly inelastic, momentum is conserved. therefore,

M1 * V1 = M2* V2

V2 = M1*V1/M2 =  5.00*10¹² *15.0 /7.36*10²²  = 1.02*10⁻⁹ km/s


5 0
3 years ago
Read 2 more answers
If the volume of a rock is 8 cm^3 and its’ mass is 16 g, what is its’ density?
attashe74 [19]
We know, Density = Mass / Volume

Substitute the given values, 
d = 16/8
d = 2 g/cm³

In short, Your Answer would be: Option C

Hope this helps!
7 0
3 years ago
PLEASE HELP! Find out whether the chemical equation is balanced or unbalanced.
nordsb [41]

One chemical reaction is called the Haber process, a method for preparing ammonia by reacting nitrogen gas with hydrogen gas:


This equation shows you what happens in the reaction, but it doesn’t show you how much of each element you need to produce the ammonia. To find out how much of each element you need, you have to balance the equation — make sure that the number of atoms on the left side of the equation equals the number of atoms on the right.


You know the reactants and the product for this reaction, and you can’t change them. You can’t change the compounds, and you can’t change the subscripts, because that would change the compounds.


So the only thing you can do to balance the equation is add coefficients, whole numbers in front of the compounds or elements in the equation. Coefficients tell you how many atoms or molecules you have.


For example, if you write the following, it means you have two water molecules:


Each water molecule is composed of two hydrogen atoms and one oxygen atom. So with two water molecules (represented above), you have a total of 4 hydrogen atoms and 2 oxygen atoms.


You can balance equations by using a method called balancing by inspection. You take each atom in turn and balance it by adding appropriate coefficients to one side or the other.


With that in mind, take another look at the equation for preparing ammonia: HOPE THIS HELPS



4 0
3 years ago
What is the frequency and energy per quantum (in Joules) of :
viktelen [127]

(a) f = 5.00 × 10²⁰ Hz, E = 3.32 × 10⁻¹³ J;

(b) f = 1.20 × 10¹⁰ Hz, E = 7.96 × 10⁻²⁴J.

<h3>Explanation</h3>

What's the similarity between a gamma ray and a microwave?

Both gamma rays and microwave rays are electromagnetic radiations. Both travel at the speed of light at 3.00 \times 10^{8}\;\text{m}\cdot\text{s}^{-1} in vacuum.

f = \dfrac{c}{\lambda}

where

  • f is the frequency of the electromagnetic radiation,
  • c is the speed of light, and
  • \lambda is the wavelength of the radiation.

(a)

Convert all units to standard ones.

\lambda = 0.600\;\text{pm} = 0.600 \times 10^{-12} \;\text{m}.

The unit of f shall also be standard.

f = \dfrac{c}{\lambda} = \dfrac{3.00\times 10^{8}\;\text{m}\cdot\text{s}^{-1}}{0.600\times 10^{12}\;\text{m}} = 5.00 \times 10^{20}\;\text{s}^{-1}= 5.00\times 10^{20}\;\text{Hz}.

For each particle,

E = h\cdot f,

where

  • E is the energy of the particle,
  • h is the planck's constant where h = 6.63\times 10^{-34}\;\text{J}\cdot\text{s}^{-1}, and
  • f is the frequency of the particle.

E = h \cdot f = 6.63\times10^{-34}\;\text{J}\cdot\text{s}\times 5.00\times 10^{20}\;\text{s}^{-1} = 3.32\times10^{-13}\;\text{J}.

(b)

Try the steps in (a) for this beam of microwave with

  • \lambda = 2.50 \;\text{cm} = 2.50\times 10^{-2}\;\text{m}.

Expect the following results:

  • f = 1.20\times 10^{10}\;\text{Hz}, and
  • E = 7.96\times 10^{-24}\;\text{J}.
4 0
3 years ago
What is the frequency of light with a wave- length of 4.0 ×10−7 m?
Kisachek [45]

7.5x10^14 Hz. I just worked it out on paper.

7 0
3 years ago
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