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LenaWriter [7]
3 years ago
5

6) Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead. Kaya slows her car from 14.0 m/s to 5.5 m/s

in 6.0 s. What is her acceleration?
Physics
1 answer:
Rashid [163]3 years ago
3 0

Answer:

The acceleration of Kaya is 1.41\ m/s^2.

Explanation:

Given that,

Initial speed of Kaya, u = 14 m/s

Final speed of Kaya, v = 5.5 m/s

Time, t = 6 s

We need to find Kaya's acceleration. We know that it is given by the change in speed per unit time. Its formula is given by :

a=\dfrac{v-u}{t}\\\\a=\dfrac{14\ m/s-5.5\ m/s}{6\ s}\\\\a=1.41\ m/s^2

So, the acceleration of Kaya is 1.41\ m/s^2. Hence, this is the required solution.

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