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3 years ago

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6) Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead. Kaya slows her car from 14.0 m/s to 5.5 m/s

in 6.0 s. What is her acceleration?

1 answer:

Rashid [163]3 years ago

3 0

Answer:

The acceleration of Kaya is $1.41\ m/s^2$ .

Explanation:

Given that,

Initial speed of Kaya, u = 14 m/s

Final speed of Kaya, v = 5.5 m/s

Time, t = 6 s

We need to find Kaya's acceleration. We know that it is given by the change in speed per unit time. Its formula is given by :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{14\ m/s-5.5\ m/s}{6\ s}\\\\a=1.41\ m/s^2$

So, the acceleration of Kaya is $1.41\ m/s^2$ . Hence, this is the required solution.

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Answer:

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From the question we are told that

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Generally from kinematic equations

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Answer:the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward.

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7. A scientist studying a squid observes that the squid at rest

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The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.

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$\overline{a} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}}$ (2)

Where:

$v_{i}$ : is the initial velocity = 0 (the squid is at rest)

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$t_{i}$ : is the initial time = 0

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Now we can find the <em>average force</em> after entering equation (2) into (1)

$F = m(\frac{v_{f} - v_{i}}{t_{f} - t_{i}}) = 0.60 kg(\frac{15.0 m/s - 0}{0.15 s}) = 60 N$

Therefore, the average force on the squid during the propulsion is 60 N.

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