Hi there!
We can begin by solving for the time it takes the projectile to reach the ground.
Use the equation:
Plug in the given height:
Use the equation:
d = vt, to solve for the horizontal distance:
d = (54)(8.536) = 460.944 m
Answer:
change in momentum is (delta,p))= 2*m*v*sin(23) ,parallel velocity to the window remains unchanged ignore, perpendicular velocity changes by twice the initial perpendicular velocity as the hail stone changes direction with respect to the perpendicular . force=total(delta,p)/t
hence force=450*2*m*v*sin(23) /46, pressure =force/area=450*2*m*v*sin(23) /46*1.187
This is not fluid mechanics,
Just think about splitting the velocity in to vector components use elastic collision fact is energy is same after collision hence so is the speed ,use known equations.
Explanation:
Answer:
slightly higher than y
Explanation:
The initial/previous upward component of the bullet's velocity does not really have effect on the constant downward acceleration due to gravity. Since you must aim upward, there will be less or declined horizontal velocity, therefore it will take more time for the bullet to get to the plane of the target or aim. The bullet will now have more time to drop away from the straight line path along which it was aimed.
Furthermore, this problem assumes ideal or perfect conditions (no effects from air resistance). The high speed of a bullet has no much or less effect in this regards.
Answer:
d. 149 ⁰C.
Explanation:
Given;
mass of the block of ice, m = 2 kg
specific heat capacity of the ice, C = 2090 J/(kgK)
initial temperature of the ice, t₁ = -90 ⁰C
heat added to the ice, H = 1,000,000 J
let the final temperature of the ice = t₂
The final temperature of the ice after adding the heat is calculated as follows;
Therefore, the new temperature of the water is 149 ⁰C.