1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kaylis [27]
3 years ago
6

Solve for k, the constant of variation, in an inverse variation problem where y=17 x=6

Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer:

k=102

Step-by-step explanation:

hope this helps with your assignment

You might be interested in
So what's the answer for 35% of 22
kondor19780726 [428]
You divide 22 by 10 (2.2) and then multiply that by 3 to get 30%, which is 6.6. Then, you divide 2.2 by 2 to get 1.1, which is 5%. After this you just add them up to get the answer as 7.7.
Also, if you have q calculator, you can do it the short way and do 22 × 0.35 = 7.7
8 0
3 years ago
Read 2 more answers
The difference of twice a number k and 8 is 12
laiz [17]

Answer:

k = 10

Step-by-step explanation:

Difference means subtract.

2k - 8 = 12

is how that statement is translated.

Add 8 to both sides.

2k - 8 + 8 = 12 + 8

2k = 20                    

Divide by 2

2k/2 = 20/2

k = 10

6 0
2 years ago
Which is the best prove why.5 gallon bucket of paint for $97.45 of a 1 gallon bucket of paint for 21.95.?
Greeley [361]
97.45 / 5 = 19.49 per gallon

and then there is 21.95 per gallon

the better deal would be the 5 gallon bucket for 97.45 because if u buy it this way, it is cheaper by the gallon
4 0
3 years ago
P(x)= 4x^3 -3x^2+5x-2​
PIT_PIT [208]

Answer:

p=4x^3−3x^2+5x−2/x

Step-by-step explanation:

Let's solve for p.

px=4x^3−3x^2+5x−2

Step 1: Divide both sides by x.

px/x=4x^3−3x^2+5x−2/x

p=4x^3−3x^2+5x−2/x

Answer:

p=4x^3−3x^2+5x−2/x

( I hope this was helpful) >;D

6 0
2 years ago
Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ
MrRissso [65]

Answer:

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

Step-by-step explanation:

We get the limits of integration:

R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq  4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace

We use the spherical coordinates and  we calculate a triple integral:

V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4  \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}}  \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\

we get:

V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

4 0
2 years ago
Other questions:
  • 50 points and brainliest for whoever gives the best and clearest answer !
    8·2 answers
  • What would the cross section of the cone be if it were cut along the dotted line shown, and you looked at it from above
    10·1 answer
  • The bacteria has an initial population of 2000 cells and increases at a rate of 40% per hour. Use the exponential function to mo
    9·2 answers
  • What is h(x) =-3x2 - 6x + 5 written in vertex form?
    11·2 answers
  • A sphere and a cone have the same volume. each figure has a radius of 3 inches.
    15·1 answer
  • All irrational numbers are integers
    6·1 answer
  • Please help
    6·1 answer
  • Evaluate the expression -5|k+3| for k=-11
    11·1 answer
  • At an airport it cost $7 to park for up to one hour and $5 per hour for each additional hour. Let x represent the number of hour
    6·1 answer
  • Question 1 GIVING BRAINLIESTT!!!!!!!!
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!