speed of current is 1.5 mi/hr
Answer:
let the rate in still water be x and rate of the current be y.
speed down the river is:
speed=distance/time
speed=14/2=7 mi/h
speed up the river is:
speed=(14)/(3.5)=4 mi/hr
thus total speed downstream and upstream will be:
x+y=7...i
x-y=4.......ii
adding the above equations i and ii we get:
2x=11
x=5.5 mi/hr
thus
y=5-5.5=1.5 mi/r
thus the speed in still waters is 5.5 mi/hr
speed of current is 1.5 mi/hr
Answer:
slope = -1
Step-by-step explanation:
y2-y1 divided by x2-x1
3-7= -4
2-(-2) = 4
-4 divided by 4 = -1
Answer:
y x (2x +y) x (7x +y)
Step-by-step explanation:
14x^2y + 9xy^2 +y^3
(Factor the expression)
y x (14x^2 +9xy +y^2)
(Rewrite the expression)
y x (14x^2 + 7xy +2xy +y^2)
(Factor the expression)
y x (7x x(2x +y) + y x (2x +y) )
(Factor the expression)
y x (2x +y) x (7x +y)
:))
I think the correct answer would be true. The quantity represented by theta is a function of time. This is because the rate of change of angular speed is constant which means the angular distance is changing with time. Hope this answers the question. Have a nice day.
