Answer:
see the attachments for the two solutions
Step-by-step explanation:
When the given angle is opposite the shorter of the given sides, there will generally be two solutions. The exception is the case where the triangle is a right triangle (the ratio of the given sides is equal to the sine of the given angle). If the given angle is opposite the longer of the given sides, there is only one solution.
When a side and its opposite angle are given, as here, the law of sines can be used to solve the triangle(s). When the given angle is included between two given sides, the law of cosines can be used to solve the (one) triangle.
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Here, the law of sines can be used to solve the triangle:
A = arcsin(a/c·sin(C)) = arcsin(25/24·sin(70°)) = 78.19° or 101.81°
B = 180° -70° -A = 31.81° or 8.19°
b = 24·sin(B)/sin(70°) = 13.46 or 3.64
Answer:
0.79 sec
Step-by-step explanation:
Given there is a tool at the top of the building which is dropped by a worker and it follows the following equation at every instant of time .

where 
We know that this height is measured from the base of the building which means that when the tool reaches the bottom of the building it has h = 0 feet.
Let this be done at time t
h(t) = 0



t = 0.79 sec
Therefore the total time taken by the tool to reach the bottom of the building is 0.79 sec.
Answer:
Look below
Step-by-step explanation:
So you know a point and the slope, now you can substitute the values of the point for the equation.