Answer:
2 FeBr3 + 3 H2So4 = Fe2(So4)3 + 6 HBr
Explanation:
<h3><u>Answer;</u></h3>
0.002512 moles of H2O
<h3><u>Explanation</u>;</h3>
The reaction between acetic acid ( CH3COOH) and NaOH is given by the equation;
CH3COOH + NaOH ------> CH3COONa + H2O
Number of moles of CH3COOH = molarity × volume in litres
= 0.08 × 31.4/1000
= 2.512 × 10^-3
Similarly number of moles of NaOH = 1 × 24.3/1000
= 0.0243
From the reaction the mole ratio of CH3COOH : NaOH
Therefore; 0.0243 moles of NaOH will react with 0.0243 moles of CH3COOH but no.of moles of CH3COOH given in the question are 0.002512 moles, which is less than what is required.
Thus; CH3COOH is the limiting reagent and amount of products produced will depend on amount of CH3COOH only.
Since; 1 mole of CH3COOH gives 1 mole of water.
Then; 0.002512 moles of CH3COOH will give 0.002512 moles of H2O
Answer:
Vapour pressure of liquid is affected by its TEMPERATURE, TYPE OF LIQUID, ADDITION OF SOLUTES.
Explanation:
Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid. Mathematically, the vapor pressure of liquid is written as:
In (Pvap) = -ΔHvap / R * (1/T) + C
ΔHvap is the enthalpy of vaporization and it is constant for specific liquid, T is the temperature and C is a constant. Temperature therefore affect the vapor pressure of a liquid as increase in temperature can cause an increase in vapor pressure.
The type of liquid also affect the vapor pressure. If the molecules bind to each other strongly in the liquid, it increases vapor pressure to be exerted by the liquid but if the type of liquid is one with weak forces of attraction, the vapor pressure is reduced.
Addition of solute to the liquid increases the boiling temperature of liquids thereby reducing it's vapor pressure.
Answer:
8.61 mL of the HCl solution
Explanation:
The reaction that takes place is:
- 2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O
From the given mass of Mg(OH)₂, we can calculate <u>the moles of HCl that are neutralized</u>:
- 4x10² mg = 400 mg = 0.400g
- 0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂
- 6.859*10⁻³ mol Mg(OH)₂ *
3.429x10⁻³ mol HCl
Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can <u>calculate the concentration using the pH value</u>:
= [H⁺]
- 0.0398 M = [H⁺] = [HCl] *Because HCl is a strong acid*
Thus, the volume is:
- 0.0398 M = 3.429x10⁻³mol HCl / Volume
- Volume = 8.616x10⁻³ L = 8.62 mL
