Question

A Canadian dime weighs 1.75g and has a thickness of 1.22mm. A Canadian quarter weighs 4.4g and has a thickness of 1.58mm. You have separate piles of dimes and quarters.
The dimes are neatly stacked into 6 piles that are each 61.0mm tall.
And, in a separate pile, there are $50 worth of quarters.
What is the mass of the total number of coins? Round you answer to the nearest whole number in g.

Answer 1

The mass of the total number of coins is 1405 g.

Since the thickness of each dime is 1.22 mm and we have each pile being 61.0 mm tall, we need to determine the number of dimes in each pile by dividing the height of the pile by the thickness of each dime.

so, number of dimes in each pile = height of each pile/thickness of each dime = 61.0 mm/1.22 mm = 50 dimes.

Since we have 6 piles, the total number of dimes in all the piles is 6 piles × 50 dimes/pile = 300 dimes.

So, there are 300 dimes in the 6 piles.

Since each dime weighs 1.75 g, 300 dimes will weigh 1.75 g/dime × 300 dimes = 525 g.

In the pile of quarters, we have $ 50 worth of quarters.

Since each quarter = $ 0.25, the number of quarters in that pile is total worth of quarter/value of one quarter = $ 50/$ 0.25 = 200 quarters.

Since each quarter weighs 4.4 g, 200 quarters will weigh 4.4 g/quarter × 200 quarters = 880 g

So, the mass of the total number of coins = total mass of dimes + total mass of quarters = 525 g + 880 g = 1405 g

So,  the mass of the total number of coins is 1405 g.

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