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2 years ago

What is the molarity of a solution with 130g of CoCl2 in 1/2 liter? (can you show the steps please)

Chemistry

1 answer:

Elden [556K]2 years ago

7 0

Answer:

Explanation:

M=mol/L

1. Find moles of CoCl2

mass of substance/molar mass = 130/129.833 = 1.001 mol

3. Substitute in molarity equation

M=(1.001/0.5)

M= around 2M

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3 years ago

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kirill115 [55]

Answer:

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Explanation:

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2 years ago

Jen can take either of two separate roads to drive to work. The first is a toll road that is rarely congested. The second road i

Alchen [17]

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3 years ago

Which of the possible compounds has a mass of 163 grams when

Simora [160]

Answer:

CH4

Explanation:

In solving this problem, we must remember that one mole of a compound contains Avogadro's number of elementary entities. These elementary entities include atoms, molecules, ions etc. Recall that one mole of a substance is the amount of substance that contains the same number of elementary entities as 12g of carbon-12. The Avogadro's number is 6.02 × 10^23.

Hence we can now say;

If 163 g of the compound contains 6.13 ×10^24 molecules

x g will contain 6.02 × 10^23 molecules

x= 163 × 6.02 × 10^23 / 6.13 × 10^24

x= 981.26 × 10^23/ 6.13 ×10^24

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6 0

3 years ago

A meteorologist balloon contains 250.0 L of He at 22.0 C and 740.0 mmHg. If the volume of the balloon can vary according to exte

NeX [460]

Answer: Option A) 240 L

Explanation:

Given that:

Initial Volume of helium (V1) = 250.0L

Initial Temperature of helium (T1) = 22.0°C

[Convert temperature in celsius to Kelvin by adding 273

(22.0°C + 273 = 295K)]

Initial Pressure of helium (P1) = 740 mmHg

[convert pressure in mmHg to atmosphere

If 760 mmHg = 1 atm

740 mmHg = 740/760 = 0.97 atm]

Final Volume of helium (V2) = ?

Final temperature T2 = -52.0°C

[Convert -52°C to Kelvin by adding 273

-52°C + 273 = 221K]

Final pressure of helium = 0.750 atm

Since pressure, volume and temperature are given, apply the combined gas equation

(P1V1)/T1 = (P2V2)/T2

(0.97 x 250.0)/295= (0.750 x V2)/221

242.5/295 = 0.750V2/221

Cross multiply

242.5 x 221 = 0.75V2 x 295

53592.5 = 221.25V2

V2 = 53592.5 / 221.25

V2 = 242.2 L (Rounded to the nearest tens, V2 becomes 240 L)

Thus, the new volume of helium at the altitude is 240 liters

5 0

3 years ago