Any value which is more than 2 standard deviations away from the mean is considered to be "unusual."
2 standard deviations above the mean 52.4 mp would be 52.4+2(1.8), or 56; 2 std devs below the mean would be 52.4 - 2(1.8), or 48.8. Thus, any value larger than 56 or any value smaller than 48.8 would be "unusual."
54.8, 49.1 and 51.3 are not unusual; 56.5 is unusual, because it's greaster than 56.
Answer:
w=25/4=6.50
Step-by-step explanation:
Answer:
B. 4 squared
Step-by-step explanation:
You have to use PEMDAS. The first one is P for parenthesis, that is the first operation you have to do.
Answer:
--- length
--- width
Step-by-step explanation:
Given
--- perimeter
--- area
Required
The dimension of the farm
Let
So:
--- perimeter
Divide by 2
Make l the subject
Also:
--- area
Substitute:
Open bracket
Rewrite as:
Factorize
Factor out w - 45
Take any one of the expression and solve for w
Recall that:
