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grandymaker [24]
2 years ago
14

10.) Find values of x and y for which ABCD must

Mathematics
1 answer:
Law Incorporation [45]2 years ago
5 0

Answer:

B x=2 y=6

Step-by-step explanation:

For ABCD to be parallelogram, following conditions should be satisfied:

2x - 0 = x + 2 & 4y - 8 = y + 10

2x - 0 = x + 2

2x - x = 2

x = 2

4y - 8 = y + 10

4y - y = 10 + 8

3y = 18

y = 18/3

y = 6

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Doesn't anyone know the answer
Nadusha1986 [10]

Answer:

d.66

have a good day

3 0
3 years ago
CAN SOMEONE PLSSS HELP WITH 27 , 28,29!
djverab [1.8K]
The area for 27 is 64cm^2.

For the mean, you add up all the numbers then divide by how many numbers there are. So you would do 45+96+100+39+50 and divide it by 5. So your mean is 66.

Now for 29.
For when n=5 is 8
For when n=8 is 14
For when n=14 is 26

Hope this helps!
3 0
3 years ago
Read 2 more answers
You are selling candy bars for the school to
Strike441 [17]

Answer:

200 bars

Step-by-step explanation:

$300 - $50 = the amount of money you still need, $250

250 dollars/$1.25 per bar = 200 bars you need to sell to get 300 dollars

7 0
3 years ago
What plus 18 equals 45?
natali 33 [55]
Okay to find what 18+?=45 just subtract 18 from 45. ANSWER: 27
8 0
3 years ago
Please please please need help on 3 and 4 I’m really lost on them
Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

5 0
3 years ago
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