Marks UP the price by 30%.
There's two ways:
30% of $22, plus $22.
OR
130% of $22.
To save time, 130% of 22.
130/100 x 22
= 13/10 x 22
=13/5 x 11
=143/5
= 28.6
$28.6
Hope this helps!
Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Hey! :)
you went on the roller coaster 7 times and the ferris wheel 5 times
Hope this helps! :)
So in order to find line AC you must find line AD and DC then plus them together.
to find AD use Pythagoras theorem
a^2 = c^2 - b^2
AD^2 = 7.5^2 - 6.5^2
AD^2 = 56.25 - 42.25
AD^2 = 14
square root both sides to get rid of the ^2
AD ≈ 3.7 or 3.74
Do the same for DC
DC^2 = 10^2 - 6.5^2
DC^2 = 100 - 42.25
DC^2 = 57.75
DC ≈ 7.6
now plus AD and DC which should give u 11.3
The answer is A. <span>Table 1 only the second table should be going by 9.6 but it isn't.</span>