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3 years ago

Geologists in Antarctica find an average of 7 meteorite fragments in every 500 tons of gravel they sift

Mathematics

1 answer:

pav-90 [236]3 years ago

6 0

Answer:

Step-by-step explanation:

Explanation: 7 fragments =500 tons of gravel. 100 fragments = 5007⋅100=7142.86 tons of gravel.

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In the diagram below p is circumscribed about quadrilateral abcd

Olegator [25]

Answer:

The correct answer option is 82°.

Step-by-step explanation:

We can see from the given diagram that the quadrilateral ABCD is inscribed in a circle.

Now using the property:

'Opposite angles in any quadrilateral inscribed in a circle are supplements of each other'. Which means that their measures add up to a total of 180 degrees.

Thus, ∠A + ∠C = 180°.

If ∠A = 100°, then ∠C = 180° - 98°.

Therefore, ∠C = 82°.

8 0

2 years ago

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A skate board ramp is built on an incline so that it rests on a porch that is 1.3m high. The bottom of the ramp is placed 2.5m f

mr_godi [17]

Answer:

θ = 27.47°

Step-by-step explanation:

This problem can be represented as a right-angled triangle, as shown in the diagram below.

To find θ, we apply the tangent part of the trigonometric ratios SOHCAHTOA:

tanθ = $\frac{opposite}{adjacent}$

In the diagram, opposite = 1.3 m and adjacent = 2.5 m

Hence:

tanθ = $\frac{1.3}{2.5}$

tanθ = 0.52

θ = $tan^{-1} 0.52$

θ = 27.47°

The ramp forms 27.47° with the ground.

8 0

3 years ago

What is the genotype of the offspring missing on the first row of the Punnett square?

lisabon 2012 [21]

Answer:

Option B

Step-by-step explanation:

On the first row of the Punnett square, the offspring inherits IA from one parent and IB from another parent hence the resulting genotype is IAIB.

7 0

3 years ago

Consider the following equation f(x)=(x^2+4)/(4x^2-4x-8)

kifflom [539]

Question:

Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)

Answer:

The vertical asymptotes are x = 2 or x = -1

Solution:

Given that,

$f(x)=\frac{x^2+4}{4x^2-4x-8}$

For vertical asymptotes, set the denominator to zero and then solve the quadratic equation

$4x^2-4x-8=0\\\\Divide\ by\ 2\\\\x^2 - 2x - 4 = 0$

$Split\ the\ middle\ term\\\\x^2+x-2x-2=0\\\\Group\ the\ equation\\\\(x^2 + x) - (2x + 2) = 0\\\\Factor\ the\ common\ term\\\\x(x + 1) - 2(x + 1) = 0\\\\(x + 1)(x - 2) = 0\\\\Therefore,\\\\x + 1 = 0\\\\x = -1\\\\And\\\\x - 2 = 0\\\\x = 2$

Thus the vertical asymptotes are x = - 1 and x = 2

3 0

3 years ago

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Can someone please help me?

vekshin1

7.2 take 1.2 and multiply by 6

5 0

2 years ago

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