PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
As you can see below, in
red is <span>g(x) = (x + 1)^3 and in
blue is f(x)=x^3. Adding 1 to x
moves the graph to the left by 1. Hope this was the answer you were looking for and I hope you have a great day!
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FOIL
x^2+11x-9x-99
x^2+2x-99
Answer:
<u><em>domain</em></u> is your <u><em>x value</em></u>, and <u><em>range</em></u> is your <u><em>y value.</em></u>
Step-by-step explanation:
Applying the angle of intersecting chords theorem, the value of z is: D. 100.
<h3>What is the Angle of Intersecting Chords Theorem?</h3>
According to the angle of intersecting chords theorem, in a circle like the one shown in the image above, where two chords intersect to form vertical angles, the theorem states that the angle formed equals half of the sum of the measures of the arcs intercepted by the angles.
Applying the angle of intersecting chords theorem, let's find x first:
73 = 1/2(96 + x)
Multiply both sides by 2
2 × (73) = 1/2(96 + x) × 2
146 = 96 + x
Subtract both sides by 96
146 - 96 = 96 + x - 96
50 = x
x = 50°
Therefore:
x + z + 96 + 114 = 360° [full circle measure]
Plug in the value of x
50 + z + 96 + 114 = 360
z + 260 = 360
Subtract both sides by 260
z + 260 - 260 = 360 - 260
z = 100°
The answer is: D. 100°.
Learn more about the angle of intersecting chords theorem on:
brainly.com/question/23732231
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