Answer:
A. H₃O⁺ + CN⁻ → H₂O + HCN
B. OH⁻ + NH₄⁺ → NH₃ + H₂O
C. CN⁻ + NH₄⁺ → HCN + NH₃
D. HSO₄⁻ + CH₃COO⁻ → SO₄²⁻ + CH₃COOH
E. ClO⁻ + NH₃ → NO REACTION
Explanation:
Part A.
Sodium cyanide consist of Na⁺ and CN⁻ ions. CN⁻ is a conjugate base and accept H⁺ ion from nitric acid to form HCN (hydrogen cyanide).
Part B.
Ammonium chloride consist of NH₄⁺ and Cl⁻ ions. Sodium hydroxide is a strong base dissociate completely in solution convert into ammonium hydroxide and sodium chloride.
Part C.
Sodium cyanide consist of counter ion Na⁺ . CN⁻ combined with ammonium bromide to form ammonium cyanide and sodium bromide.
Part D.
Potassium hydrohen sulphate consist of potassium counter and hydrogen sulphate ion. Hydrogen sulphate combined with acetate ion to form acetic acid and sulphate ion.
Part E.
There have no reaction because hypochlorite and ammonia both are bases.
Answer:
n = 3
Explanation:
Given the formula for the transition energy of an atom with 1 electron:
For the H transition n=5 to n=2:
Then we solve for nf with Z=2 (Helium)
Is near 3, actually the energy of the transitions are:
H (5⇒2) = -2.85 eV = 434 nm (Dark blue)
He (4⇒3) = -2.64 eV = 469 nm (Light blue)
I thought it was cool to see the actual colors. Included them.
Answer:
Answer:
12. 5
11.
10
10
15. 7
14. 11
2
=
16
16
18. 3
+
11
17
3
4
co
loo
8
Step-by-step explanation:
12. 5
11.
10
10
15. 7
14. 11
Answer:
The elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups.
Each row represents one period; the period number of an element indicates how many of its energy levels house electrons. Sodium, for instance, sits in the third period, which means a sodium atom typically has electrons in the first three energy levels.
Explanation:
Fluorine, Chlorine, Bromine, Iodine and Astatine are representing the family of elements called : halogens.
Halogens:
- all have 7 electrons in their outer shell,
- are very reactive elements,
- form - 1 ions.
Answer: C ) They have same chemical properties.
