<span>vegetable oils are unsaturated so it would create a more liquid soap, while animal fats are saturated so it creates a more solid soap</span>
Answer:
Hi! hopefully this helps you
Explanation:
You can make a buffer solution for a specific pH (potential of hydrogen) by mixing together a weak acid like acetic acid HC2H3O2 with a salt that contains the conjugate base like sodium acetate NaC2H3O2. A neutralization reaction would occur as you are mixing a weak acid and a strong base.
When you add the base to an acidic solution, the solution becomes less acidic and moves toward the middle of the pH scale. Aka neutralization
Hope this helps! best of luck <3
Answer: It's D
Explanation:
I just did this question and i picked C but it's actually D
Answer:
Chromatography is a method of separation of materials from a mixture. Paper chromatography is a technique of separation where, paper used as a stationary phase and solvent used to separate the sample used as a mobile phase. The sample is applied over the paper in small quantity. The components of the sample separates in a chromatographic paper due to the movement of solvent. The components of the sample moves with the solvent.
Paper chromatography is a useful technique for ink analysis. Ink consists of several dyes, which can be separated individually. When the ink is exposed to certain solvent mixtures the dyes of the ink dissolves in the mixture. Each ink components acquire distinct distance according to the retention factor. Some inks are water soluble, so the solvent used for separation should be water. Inks which are not water soluble are soluble in other solvents like alcohol.
We can use the ideal gas law equation to find the pressure
PV = nRT
where;
P - pressure
V - volume - 3.9 x 10⁻³ m³
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 45 °C + 273 = 318 K
n - number of moles
there are 6.022 x 10²³ molecules in 1 mol of H₂
Therefore when theres 2.6 x 10²³ H₂ molecules - 1 / (6.022 x 10²³) x 2.6 x 10²³
Number of H₂ moles - 0.43 mol
substituting these values in the equation,
P x 3.9 x 10⁻³ m³ = 0.43 mol x 8.314 Jmol⁻¹K⁻¹ x 318 K
P = 291.5 kPa