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Setler [38]
2 years ago
6

A marine biologist and her team capture 40 sea turtles and mark them before releasing them. The following year, they capture 60

sea turtles at the same location. Of the 60 sea turtles, only 15 have the mark from the prior year. What is the estimated population of sea turtles for that location?
7 sea turtles
23 sea turtles
160 sea turtles
240 sea turtles
Chemistry
1 answer:
NARA [144]2 years ago
3 0

The estimated population of the sea turtles for that location is 160 turtles  

Let b represent the total turtles in the location.

<h3>Data obtained from the question</h3>
  • Marked turtle = 40
  • Captured turtle = 60
  • Captured marked turtle = 15
  • Total turtle = b =?

The estimated turtles in sea can be obtained as follow:

Mark in sea / Total in sea = captured marked turtle / Captured turtle

40 / b = 15 / 60

Cross multiply

b × 15 = 40 × 60

b × 15 = 2400

Divide both side by 15

b = 2400 / 15

b = 160 turtles

Thus, the estimated turtles in the sea is 160 turtles

Learn more about estimation:

brainly.com/question/9583992

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Answer:

B.) An atom of arsenic has one more valence electron and more electron shells than an atom of silicon, so the conductivity decreases because the arsenic atom loses the electron.

Explanation:

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Natural vs. Synthetic
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8 0
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Fittoniya [83]

Answer:

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Explanation:

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Which of the followings is true about G0'? A. G0' can be determined using Keq' B. G0' indicates if a reaction can occur under no
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Answer:

A and D are true , while B and F statements are false.

Explanation:

A) True.  Since the standard gibbs free energy is

ΔG = ΔG⁰ + RT*ln Q

where Q= [P1]ᵃ.../([R1]ᵇ...) , representing the ratio of the product of concentration of chemical reaction products P and the product of concentration of chemical reaction reactants R

when the system reaches equilibrium ΔG=0 and Q=Keq

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ΔG⁰ = (-RT*ln Keq)

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D) True. Standard conditions refer to

T= 298 K

pH= 7

P= 1 atm

C= 1 M for all reactants

Water = 55.6 M

5 0
2 years ago
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