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Arte-miy333 [17]
3 years ago
12

Can someone help me??

Chemistry
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer: B. ridge push and slab pull

Explanation: Took the test.

Kryger [21]3 years ago
6 0

Answer:

I do K12 and c is correct!

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1. Round each of the following numbers to four significant figures, and express the result in scientific notation:
vfiekz [6]

The rounding up of the aforementioned number to four significant figures is as follows: 3.002 × 10²

<h3>What are significant figures?</h3>

Significant figures are figures that contribute to the general and overall value of the whole number.

Significant figures or digits are specifically meaningful with respect to the precision of a measurement.

Although, the original number given in this question has 9 significant figures, the number; 300.235800 can be rounded up to four significant figures as follows:

  • Decimal notation: 300.2
  • No. of significant figures: 4
  • No. of decimals: 1
  • Scientific notation: 3.002 × 10²

Therefore, the rounding up of the aforementioned number to four significant figures is as follows: 3.002 × 10².

Learn more about significant figures at: brainly.com/question/14359464

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3 0
1 year ago
NaOH is typically standardized using potassium hydrogen phthalate (KHP).
DaniilM [7]

Answer:

Na(OH)²

Explanation:

We look for the charges in the periodic table

6 0
2 years ago
A beam of light passes though a liquid in a test tube without scattering. Which type of mixture is most likely in the test tube?
butalik [34]
The answer would be letter C - solution.

A mixture should be homogeneous for a light not to be scattered. This is because particles are distributed evenly throughout the mixture which allows light to pass directly. In your choices, the solution allows a  beam of light to pass through a liquid in a test tube without scattering.
6 0
3 years ago
Read 2 more answers
The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm. A hydrogen emission spectrum has a violet, a blue,
Sloan [31]

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

Wavelength, λ = 486.0 nm

As we know,

E=h\upsilon =\frac{hc}{\lambda}

On putting the estimated values, we get

⇒          =\frac{1241.5 \ ev\ nm}{486 \ nm}

⇒          =2.554 \ ev

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, E=2.554\times 1.6\times 10^{-19}

⇒               =4.08\times 10^{-19} Joule

7 0
3 years ago
Is germahium a metal?
MA_775_DIABLO [31]
Germanium is classified as a metalloid or semi-metal . (:
4 0
2 years ago
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