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2 years ago

First one to answer randomly gets brainliest!

Mathematics

2 answers:

s344n2d4d5 [400]2 years ago

4 0

Answer:

Step-by-step explanation:

Lerok [7]2 years ago

4 0

Answer:

Patrick Mahomes and a Chicken.

Step-by-step explanation:

Brainliest please! Visit my church's website at fbcinterlaken.org to learn more about God! It would mean a lot if you could also subscribe to the You Tube channel as well! Thank you and have a nice day! :)

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How many sides do 3 octagons and 3 pentagons have in all?

Neporo4naja [7]

39 sides is the answer to it

3 0

3 years ago

Read 2 more answers

At the start of 2014, Mike's car is worth 12000. the car depreciates by 30 percent every year. how much is his car worth in 2017

Anarel [89]

Answer:

$4,116

Step-by-step explanation:

Worth of Mike's car at the start of 2014 = $12,000

If the car is said to depreciates every year by 30% = 30/100 = 0.3

The worth of the car at the start of 2017 is what we are to determine.

This means that the car depreciated by 30% (0.3) for 3 years since 2014 (2017 - 2014 = 3 yrs)

The worth at the start of 2017 would be calculated as follows:

12,000 × (1 - 0.3)³

= 12,000 × (0.7)³

= 12,000 × 0.343

= 4,116

Worth of the car at the start of 2017 would be $4,116

4 0

3 years ago

Which of the following is a function equivalent to f(x) = 5(1.9)3x?

Sophie [7]

B. f(x)=5(6.86x) this the correct anwser

6 0

3 years ago

Read 2 more answers

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$