It's 416,666,667/1,000,000,000. //// If you said that the 6s keep going and never end, then it would be the decimal form of 5/12 .
If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
<h3>What is the z-score?</h3>
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
More about the z-score link is given below.
brainly.com/question/15016913
#SPJ1
The product of a number y and 12 or 12 times a number y. These are both equivalent expressions to 12y
Answer:
Step-by-step explanation:
Hello!
I'll express all the given percentages as probabilities:
Given the events:
Banking online (Bo)
Under the age of 50 (<50)
P(Bo)= 0.30
P(<50)= 0.40
P(Bo ∩ <50)= 0.25
1) What percentage of adults do not conduct their banking online?
The event "adults that do not conduct their baking online" is the complement of the event "adults that conduct their baking online" Symbolically 
P()= 1 - P(Bo)= 1 - 0.30 = 0.70
2) What type of probability is 25%?
The probability P(Bo ∩ <50)= 0.25 is a joint probability, it indicates the intersection between both events.
3) Construct a contingency table showing all joint and marginal probabilities.
Check attachment.
4) What is the probability that an individual conducts banking online given that the individual is under the age of 50?
Symbolically:
P(Bo/<50)= <u> P(Bo ∩ <50) </u> = <u> 0.25 </u> = 0.625
P(<50) 0.40
I hope it helps!
I agree with the other person that this is 25% error
